Does javascript use binary code?

I know that 0x is a prefix for hexadecimal numbers in Javascript. For example, 0xFF stands for the number 255.

Is there something similar for binary numbers ? I would expect 0b1111 to represent the number 15, but this doesn't work for me.

asked May 10, 2010 at 13:59

Misha MoroshkoMisha Moroshko

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6

Update:

Newer versions of JavaScript -- specifically ECMAScript 6 -- have added support for binary (prefix 0b), octal (prefix 0o) and hexadecimal (prefix: 0x) numeric literals:

var bin = 0b1111;    // bin will be set to 15
var oct = 0o17;      // oct will be set to 15
var oxx = 017;       // oxx will be set to 15
var hex = 0xF;       // hex will be set to 15
// note: bB oO xX are all valid

This feature is already available in Firefox and Chrome. It's not currently supported in IE, but apparently will be when Spartan arrives.

(Thanks to Semicolon's comment and urish's answer for pointing this out.)

Original Answer:

No, there isn't an equivalent for binary numbers. JavaScript only supports numeric literals in decimal (no prefix), hexadecimal (prefix 0x) and octal (prefix 0) formats.

One possible alternative is to pass a binary string to the parseInt method along with the radix:

var foo = parseInt('1111', 2);    // foo will be set to 15

Qwerty

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answered May 10, 2010 at 14:04

14

In ECMASCript 6 this will be supported as a part of the language, i.e. 0b1111 === 15 is true. You can also use an uppercase B (e.g. 0B1111).

Look for NumericLiterals in the ES6 Spec.

Olga

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answered Sep 1, 2014 at 22:20

urishurish

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I know that people says that extending the prototypes is not a good idea, but been your script...

I do it this way:

Object.defineProperty(
    Number.prototype, 'b', {
        set:function(){
            return false;
        },

        get:function(){
            return parseInt(this, 2);
        }
    }
);


100..b       // returns 4
11111111..b  // returns 511
10..b+1      // returns 3

// and so on

ruffin

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answered Sep 26, 2012 at 7:27

Juan GarciaJuan Garcia

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If your primary concern is display rather than coding, there's a built-in conversion system you can use:

var num = 255;
document.writeln(num.toString(16)); // Outputs: "ff"
document.writeln(num.toString(8)); // Outputs: "377"
document.writeln(num.toString(2)); // Outputs: "11111111"

Ref: MDN on Number.prototype.toString

ruffin

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answered May 10, 2010 at 14:18

PopsPops

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As far as I know it is not possible to use a binary denoter in Javascript. I have three solutions for you, all of which have their issues. I think alternative 3 is the most "good looking" for readability, and it is possibly much faster than the rest - except for it's initial run time cost. The problem is it only supports values up to 255.

Alternative 1: "00001111".b()

String.prototype.b = function() { return parseInt(this,2); }

Alternative 2: b("00001111")

function b(i) { if(typeof i=='string') return parseInt(i,2); throw "Expects string"; }

Alternative 3: b00001111

This version allows you to type either 8 digit binary b00000000, 4 digit b0000 and variable digits b0. That is b01 is illegal, you have to use b0001 or b1.

String.prototype.lpad = function(padString, length) {
    var str = this;
    while (str.length < length)
        str = padString + str;
    return str;
}
for(var i = 0; i < 256; i++)
    window['b' + i.toString(2)] = window['b' + i.toString(2).lpad('0', 8)] = window['b' + i.toString(2).lpad('0', 4)] = i;

answered Sep 12, 2012 at 21:52

frodeborlifrodeborli

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May be this will usefull:

var bin = 1111;
var dec = parseInt(bin, 2);
// 15

answered Dec 9, 2011 at 12:25

Sergey MetlovSergey Metlov

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No, but you can use parseInt and optionally omit the quotes.

parseInt(110, 2); // this is 6 
parseInt("110", 2); // this is also 6

The only disadvantage of omitting the quotes is that, for very large numbers, you will overflow faster:

parseInt(10000000000000000000000, 2); // this gives 1
parseInt("10000000000000000000000", 2); // this gives 4194304

answered Oct 14, 2014 at 13:11

0

I know this does not actually answer the asked Q (which was already answered several times) as is, however I suggest that you (or others interested in this subject) consider the fact that the most readable & backwards/future/cross browser-compatible way would be to just use the hex representation.

From the phrasing of the Q it would seem that you are only talking about using binary literals in your code and not processing of binary representations of numeric values (for which parstInt is the way to go).

I doubt that there are many programmers that need to handle binary numbers that are not familiar with the mapping of 0-F to 0000-1111. so basically make groups of four and use hex notation.

so instead of writing 101000000010 you would use 0xA02 which has exactly the same meaning and is far more readable and less less likely to have errors.

Just consider readability, Try comparing which of those is bigger:
10001000000010010 or 1001000000010010

and what if I write them like this:
0x11012 or 0x9012

answered May 26, 2015 at 12:15

epelegepeleg

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Convert binary strings to numbers and visa-versa.

var b = function(n) {
    if(typeof n === 'string')
        return parseInt(n, 2);
    else if (typeof n === 'number')
        return n.toString(2);
    throw "unknown input";
};

answered Jan 4, 2013 at 11:04

jpillorajpillora

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Using Number() function works...

// using Number() 
var bin = Number('0b1111');    // bin will be set to 15
var oct = Number('0o17');      // oct will be set to 15
var oxx = Number('0xF');       // hex will be set to 15

// making function convTo
const convTo = (prefix,n) => {
  return Number(`${prefix}${n}`) //Here put prefix 0b, 0x and num
}

console.log(bin)
console.log(oct)
console.log(oxx)

// Using convTo function
console.log(convTo('0b',1111))

answered Nov 22, 2021 at 16:55

RazerJsRazerJs

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