How do you find all the positive numbers in a list python?

Given a list of numbers, write a Python program to print all positive numbers in given list. 

Example:

Input: list1 = [12, -7, 5, 64, -14]
Output: 12, 5, 64

Input: list2 = [12, 14, -95, 3]
Output: [12, 14, 3]

Example #1: Print all positive numbers from given list using for loop Iterate each element in the list using for loop and check if number is greater than or equal to 0. If the condition satisfies, then only print the number. 

Python3

list1 = [11, -21, 0, 45, 66, -93]

for num in list1:

    if num & gt

    = 0:

        print(num, end=& quot

              & quot

              )

Output:

11 0 45 66 

  Example #2: Using while loop 

Python3

list1 = [-10, 21, -4, -45, -66, 93]

num = 0

while(num < len(list1)):

    if list1[num] >= 0:

        print(list1[num], end = " ")

    num += 1

Output:

21 93 

  Example #3: Using list comprehension 

Python3

list1 = [-10, -21, -4, 45, -66, 93]

pos_nos = [num for num in list1 if num >= 0]

print("Positive numbers in the list: ", *pos_nos)

Output:

Positive numbers in the list:  45 93

  Example #4: Using lambda expressions 

Python3

list1 = [-10, 21, 4, -45, -66, 93, -11]

pos_nos = list(filter(lambda x: (x >= 0), list1))

print("Positive numbers in the list: ", *pos_nos)

Output:

Positive numbers in the list:  21, 4, 93

Method: Using enumerate function 

Python3

l=[12, -7, 5, 64, -14]

print([a for j,a in enumerate(l) if a>=0])

Method:Using startswith() method

Python3

list1 = [11, -21, 0, 45, 66, -93]

res=[]

list2=list(map(str,list1))

for i in range(0,len(list2)):

    if( not list2[i].startswith("-") and list2[i] !="0"):

        res.append(str(list1[i]))

res=" ".join(res)

print(res)

Auxiliary Space: O(1)

Method: Using Numpy Array: 

Python

import numpy as np

list1 = np.array([-10, -21, -4, 45, -66, 93])

pos_nos = list1[list1 >=0];

print("Positive numbers in the list: ", *pos_nos)

Output:

Positive numbers in the list:  45 93

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