How many 3 digit numbers can be formed from the digits 5, 6, 7, 8 and 9 if no repetition is allowed

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Given the numbers $1$, $5$, $7$, $8$, and $9$, how many $3$-digit numbers larger than $700$ can be formed if repetition is not allowed?

The answer is $36$.

I want a detailed explanation please of how we get this answer?

asked Apr 15, 2017 at 13:53

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0

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Let your number be $ABC$,
$A $ can take up values 7,8 and 9 i.e. total 3. Now $B$ has total 4 choices and simultaneously $C$ will have 3.
Thus answer=4*3*3=36

Example: Let $A$=7. Thus $B$ is left with {1,5,8,9}.
Let $B$ be 5. Thus now $C$ is left with {1,8,9}. Clear?

answered Apr 15, 2017 at 13:56

How many 3 digit numbers can be formed from the digits 5, 6, 7, 8 and 9 if no repetition is allowed

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How many numbers of 3 digits can be formed with the digits 5,6,7,8,9 repetition of the digits not allowed?

Question

A

30

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B

60

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C

120

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D

240

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Solution

The correct option is B 60=5×4×3=60

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Similar questions

Q.

How many 3-digit numbers can be formed from the digits 1, 2, 3, 4 and 5 assuming that

(i) repetition of the digits is allowed?

(ii) repetition of the digits is not allowed?

How many three digit numbers can be formed by using the digits 1 7 8 9 repetition is allowed?

Hence, the required number of numbers =504. Q.

How many 3

∴ Required number of numbers = (1 x 5 x 4) = 20.

How many three digit numbers can be formed by using the digits 2 5 6 8 and 0 repetition of digits is not allowed?

Answer: 60. Let 3-digit number be XYZ.

How many 3 digits can be formed?

So the number of digits available for B = 4 (As one digit has already been chosen at A), Similarly, the number of digits available for C = 3. Thus, The total number of 3-digit numbers that can be formed = 5 × 4 × 3 = 60.