    # How many different ways can the letters of the word corporation be arranged so that the vowels always come together?

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• The correct option is A 50400In the word 'CORPORATION', we’ll treat the vowels OOAIO as a single letter. Thus, we have CRPRTN (OOAIO). This has 7 (6 + 1) letters of which R occurs 2 times and the rest are different. Number of ways of arranging these letters =7!2!!=2520 Now, 5 vowels in which O occurs 3 times and the rest are different, can be arranged In 5!3!=20 ways Therefore, Required number of ways =(2520×20)=50400
• Question Detail
• 1. A box contains 4 red, 3 white and 2 blue balls. Three balls are drawn at random. Find out the number of ways of selecting the balls of different colours
• 2. Evaluate permutation equation \begin{aligned} ^{59}{P}_3 \end{aligned}
• 3. In how many words can be formed by using all letters of the word BHOPAL
• 4. Evaluate permutation equation \begin{aligned} ^{75}{P}_2\end{aligned}
• 5. How many words can be formed by using all letters of TIHAR
• How many different ways CORPORATION be arranged so that vowels come together?
• How many different ways can the letters of the word CORPORATION be arranged so that the vowels always come together Mcq?
• How many ways can the letters of the word CORPORATION be arranged so that vowels always occupy even places?
• How many words can be formed from the word CORPORATION?

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Solution

## The correct option is A 50400In the word 'CORPORATION', we’ll treat the vowels OOAIO as a single letter. Thus, we have CRPRTN (OOAIO). This has 7 (6 + 1) letters of which R occurs 2 times and the rest are different. Number of ways of arranging these letters =7!2!!=2520 Now, 5 vowels in which O occurs 3 times and the rest are different, can be arranged In 5!3!=20 ways Therefore, Required number of ways =(2520×20)=50400

### Question Detail

• 5760
• 50400
• 2880
• None of above

Explanation:

Vowels in the word "CORPORATION" are O,O,A,I,O
Lets make it as CRPRTN(OOAIO)

This has 7 lettes, where R is twice so value = 7!/2!
= 2520

Vowel O is 3 times, so vowels can be arranged = 5!/3!

= 20

Total number of words = 2520 * 20 = 50400

Similar Questions :

## 1. A box contains 4 red, 3 white and 2 blue balls. Three balls are drawn at random. Find out the number of ways of selecting the balls of different colours

• 12
• 24
• 48
• 168

Explanation:

This question seems to be a bit typical, isn't, but it is simplest.
1 red ball can be selected in 4C1 ways
1 white ball can be selected in 3C1 ways
1 blue ball can be selected in 2C1 ways

Total number of ways
= 4C1 x 3C1 x 2C1
= 4 x 3 x 2
= 24

Please note that we have multiplied the combination results, we use to add when their is OR condition, and we use to multiply when there is AND condition, In this question it is AND as
1 red AND 1 White AND 1 Blue, so we multiplied.

## 2. Evaluate permutation equation \begin{aligned} ^{59}{P}_3 \end{aligned}

• 195052
• 195053
• 195054
• 185054

Explanation:

\begin{aligned}
^n{P}_r = \frac{n!}{(n-r)!} \\
^{59}{P}_3 = \frac{59!}{(56)!} \\
= \frac{59 * 58 * 57 * 56!}{(56)!} \\
= 195054
\end{aligned}

• 420
• 520
• 620
• 720

Explanation:

Required number
\begin{aligned}
= 6! \\
= 6*5*4*3*2*1 \\
= 720
\end{aligned}

## 4. Evaluate permutation equation \begin{aligned} ^{75}{P}_2\end{aligned}

• 5200
• 5300
• 5450
• 5550

Explanation:

\begin{aligned}
^n{P}_r = \frac{n!}{(n-r)!} \\
^{75}{P}_2 = \frac{75!}{(75-2)!} \\
= \frac{75*74*73!}{(73)!} \\
= 5550

\end{aligned}

## 5. How many words can be formed by using all letters of TIHAR

• 100
• 120
• 140
• 160

Explanation:

First thing to understand in this question is that it is a permutation question.
Total number of words = 5
Required number =
\begin{aligned}
^5{P}_5 = 5! \\
= 5*4*3*2*1 = 120
\end{aligned}

Read more from - Permutation and Combination Questions Answers

• #### Fernando Fidel Flores 8 years ago

what has 7 letters?
I only counted 6 consonants and 5 vowels.

#### mastguru 8 years ago replied

Hello Fernando,

As per solution we have written like CRPRTN(OOAIO)

Here we take it 7 letters , 6 (CRPRTN) + 1 (OOAIO), as we need to vowel always come together, this way we counted them 7. Then solved the question.
Hope it helped you..

• #### Gabriela 9 years ago

THANK YOU SOOO MUCH, IT WAS FRO A HOMEWORK AND I WAS SO CONFUSED, I KNOW HOW TO DO COMBINATIONS AND PERMUTATIONS BUT I WASNT SURE OF WICH OF THEM TO USE AND HOW TO WRITE IT....THANKS :)

• 1

### How many different ways CORPORATION be arranged so that vowels come together?

So, the total number of ways of arranging the letters of the word 'CORPORATION' be arranged so that the vowels always come together are 7!

### How many different ways can the letters of the word CORPORATION be arranged so that the vowels always come together Mcq?

Therefore, Required number of ways =(2520×20)=50400.

### How many ways can the letters of the word CORPORATION be arranged so that vowels always occupy even places?

60 ways. Originally Answered: In how many ways can the letters of word “corporation” be arranged so that each vowel occupies even places? It is an 11 lettered word with 5 vowels (3 o's and 1 a & 1 i) and 6 consonants. Moreover, there are 5 even places and 6 odd places.

### How many words can be formed from the word CORPORATION?

There are in all 11 letters in the word CORPORATION. Since, Repetition is not allowed, there are 8 different letters that can be used to form 3-letter word. Therefore, total number of words that can be formed = 8P3 = (8 × 7 × 6) = 336.

### How many different ways the letters of word corporation be arranged so that vowels come together?

∴ Required number of ways = (2520 x 20) = 50400. Was this answer helpful?

### How many ways can the letters of the word corporation be arranged?

Required number of ways = (120 x 6) = 720. In how many different ways can the letters of the word 'CORPORATION' be arranged so that the vowels always come together? E. 