How to change delimiter in list python

I have a list

[u'Scanned by CamS\nINCOME TAN DEPARTMENT\nINDER SINGH\nAMAR JEETSINGH FIORA\n2407/1985\nMimi\nAAPPF5793,\nGOVT of INDIA\n']

is there a way to change the list separator from '\n' to ',' using python?

My expected output is

['Scanned by CamS','INCOME TAN DEPARTMENT','INDER SINGH','AMAR JEETSINGH FIORA','2407/1985','Mimi','AAPPF5793,','GOVT of INDIA']

This is fake PAN.

asked Feb 28, 2017 at 5:34

Dipanwita DasDipanwita Das

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7

using split on first list item (desired string) :

l = [u'Scanned by CamS\nINCOME TAN DEPARTMENT\nINDER SINGH\nAMAR JEETSINGH FIORA\n2407/1985\nMimi\nAAPPF5793,\nGOVT of INDIA\n']
l =  l[0].split('\n')
l # ['Scanned by CamS', 'INCOME TAN DEPARTMENT', 'INDER SINGH', 'AMAR JEETSINGH FIORA', '2407/1985', 'Mimi', 'AAPPF5793,', 'GOVT of INDIA', '']

last element is empty because of last '\n'

answered Feb 28, 2017 at 5:38

ᴀʀᴍᴀɴᴀʀᴍᴀɴ

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You can try this both..

a = [u'Scanned by CamS\nINCOME TAN DEPARTMENT\nINDER SINGH\nAMAR JEETSINGH FIORA\n2407/1985\nMimi\nAAPPF5793,\nGOVT of INDIA\n']

print str(a[0]).split('\n')
#['Scanned by CamS', 'INCOME TAN DEPARTMENT', 'INDER SINGH', 'AMAR JEETSINGH FIORA', '2407/1985', 'Mimi', 'AAPPF5793,', 'GOVT of INDIA', '']

print str(a[0]).replace('\n',' ,')
#Scanned by CamS ,INCOME TAN DEPARTMENT ,INDER SINGH ,AMAR JEETSINGH FIORA ,2407/1985 ,Mimi ,AAPPF5793, ,GOVT of INDIA ,

answered Feb 28, 2017 at 5:48

Shivkumar kondiShivkumar kondi

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2

Given List of Strings and replacing delimiter, replace current delimiter in each string.

Input : test_list = [“a, t”, “g, f, g”, “w, e”, “d, o”], repl_delim = ‘ ‘
Output : [“a t”, “g f g”, “w e”, “d o”]
Explanation : comma is replaced by empty spaces at each string.

Input : test_list = [“g#f#g”], repl_delim = ‘, ‘
Output : [“g, f, g”]
Explanation : hash is replaced by comma at each string.

Method #1 : Using replace() + loop
The combination of above functions provide a brute force method to solve this problem. In this, a loop is used to iterate through each string and perform replacement using replace().

test_list = ["a, t", "g, f, g", "w, e", "d, o"] 

print("The original list is : " + str(test_list))

repl_delim = '#'

res = []

for ele in test_list:

    res.append(ele.replace(", ", repl_delim))

print("Replaced List : " + str(res))

Output :

The original list is : ['a, t', 'g, f, g', 'w, e', 'd, o']
Replaced List : ['a#t', 'g#f#g', 'w#e', 'd#o']

Method #2 : Using list comprehension + replace()
The combination of above functions can provide one liner to this problem. This is similar to above method, just encapsulated in list comprehension.

test_list = ["a, t", "g, f, g", "w, e", "d, o"] 

print("The original list is : " + str(test_list))

repl_delim = '#'

res = [sub.replace(', ', repl_delim) for sub in test_list]

print("Replaced List : " + str(res))

Output :

The original list is : ['a, t', 'g, f, g', 'w, e', 'd, o']
Replaced List : ['a#t', 'g#f#g', 'w#e', 'd#o']

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