How to get letters from a word in python

The easiest way is probably just to use list(), but there is at least one other option as well:

s = "Word to Split"
wordlist = list(s)               # option 1, 
wordlist = [ch for ch in s]      # option 2, list comprehension.

They should both give you what you need:

['W','o','r','d',' ','t','o',' ','S','p','l','i','t']

As stated, the first is likely the most preferable for your example but there are use cases that may make the latter quite handy for more complex stuff, such as if you want to apply some arbitrary function to the items, such as with:

[doSomethingWith(ch) for ch in s]

Split a word into a list of letters in Python #

Use the list() class to split a word into a list of letters, e.g. my_list = list(my_str). The list() class will convert the string into a list of letters.

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my_str = 'hello'

my_list = list(my_str)

# 👇️ ['h', 'e', 'l', 'l', 'o']
print(my_list)

The list class takes an iterable and returns a list object.

When a string is passed to the class, it splits the string on each character and returns a list containing the characters.

An alternative approach is to use a list comprehension.

Use a list comprehension to split a word into a list of letters, e.g. my_list = [letter for letter in my_str]. List comprehensions are used to perform some operation for every element, or select a subset of elements that meet a condition.

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my_str = 'hello'
my_list = [letter for letter in my_str]
# 👇️ ['h', 'e', 'l', 'l', 'o']
print(my_list)

You can also filter letters out of the final list when using this approach.

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my_str = 'h e l l o'

my_list = [letter for letter in my_str if letter.strip()]

# 👇️ ['h', 'e', 'l', 'l', 'o']
print(my_list)

The string in the example has spaces.

Instead of getting list items that contain a space, we call the strip() method on each letter and see if the result is truthy.

The str.strip method returns a copy of the string with the leading and trailing whitespace removed.

If the string stores a space, it would get excluded from the final list.

You can also use a simple for loop to split a word into a list of letters.

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my_str = 'hello'

my_list = []

for letter in my_str:
    my_list.append(letter)

# 👇️ ['h', 'e', 'l', 'l', 'o']
print(my_list)

We used a for loop to iterate over the string and use the append method to add each letter to the list.

The list.append() method adds an item to the end of the list.

The method returns None as it mutates the original list.

You can also conditionally add the letter to the list.

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my_str = 'hello'

my_list = []

for letter in my_str:
    if letter.strip() != '':
        my_list.append(letter)

# 👇️ ['h', 'e', 'l', 'l', 'o']
print(my_list)

The string is only added to the list if it isn't a space.

"APPLE" variables: p="A" q="P" r="P" s="L" t="E"

Simple a,b,c,d,e = "apple" print(a) print(b) print(c) print(d) print(e) Any char in string can also be accessed by index s = "apple" then 'a' is at s[0] 'b is at s[1] etc. Indexing starts from 0

Store the string "APPLE" in a variable, let's say fruit. fruit[0] will return "A" fruit[1] will return "B" And so on. Hope that helps. Use a loop if required. len(string) will return the length of string as an integer.

Just declare a variable.Let str. Then str="APPLE" #assign value At last Print(str[0],end="") Print(str[1],end="") Print(str[2],end="") Print(str[3],end="") Print(str[4],end="") Like this u can print single character of string

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