Print e pattern in python

Python Conditional: Exercise - 19 with Solution

Write a Python program to print alphabet pattern 'E'.

Pictorial Presentation:

Sample Solution:

Python Code:

result_str="";    
for row in range(0,7):    
    for column in range(0,7):     
        if (column == 1 or ((row == 0 or row == 6) and (column > 1 and column < 6)) or (row == 3 and column > 1 and column < 5)):  
            result_str=result_str+"*"    
        else:      
            result_str=result_str+" "    
    result_str=result_str+"\n"    
print(result_str);

Sample Output:

 *****                                                                                                        
 *                                                                                                            
 *                                                                                                            
 ****                                                                                                         
 *                                                                                                            
 *                                                                                                            
 *****  

Flowchart :

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Previous: Write a Python program to print alphabet pattern 'D'.
Next: Write a Python program to print alphabet pattern 'G'.

August 2, 2020 August 2, 2020

Hello everyone! Welcome back to programminginpython.com. I am continuing with this pattern programming series, here I will tell you how to print the pattern of the letter ‘E’. In the previous tutorials, I have shown you the pattern for the letter ‘D’, letter C, letter A, and letter B. Here it’s now time for Pattern E.

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Print Pattern E – Code Visualization

Task:

Python program to print the pattern of letter ‘E’

Approach:

• Read an input integer for asking the size of the letter using input()
• Check if the entered number is greater than 8,
  • if yes, call the function print_pattern()
  • else, show a message to enter a number which is greater or equal to 8
• print_pattern()
  • here we only do two things, print star(*) and print space( ), just writing conditions so the pattern of *‘s and ‘s will display the pattern ‘E’
  • following are 3 conditions for printing *’s
    We have 2 loops, outer loop() for rows and inner loop for columns.

  • # Outer for loop
        for row in range(n): 
      
            # Inner for loop 
            for column in range(n - 2):

    • Print first and last row and middle row

      • ((row == 0 or row == n-1 or row == n//2 )

    • Print first column

      • column == 0

  • print in remaining all cases.

Program:

__author__ = 'Avinash'

# Python3 program to print alphabet E pattern

# *********
# *
# *
# *
# *********
# *
# *
# *********


def print_pattern(n):
    # Outer for loop for number of rows
    for row in range(n):

        # Inner for loop columns
        for column in range(n):

            # prints first and last and middle row
            if ((row == 0 or row == n - 1 or row == n // 2) or

                    # prints first column
                    column == 0):
                print("*", end="")
            else:
                print(" ", end="")
        print()


size = int(input("Enter size: \t"))

if size < 8:
    print("Enter a size greater than 8")
else:
    print_pattern(size)

Output: