How do I search for items that contain the string 'abc' in the following list?
xs = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
The following checks if 'abc' is in the list, but does not detect 'abc-123' and 'abc-456':
if 'abc' in xs:
asked Jan 30, 2011 at 13:29
3
To check for the presence of 'abc' in any string in the list:
xs = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
if any["abc" in s for s in xs]:
...
To get all the items containing 'abc':
matching = [s for s in xs if "abc" in s]
Mateen Ulhaq
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answered Jan 30, 2011 at 13:32
Sven MarnachSven Marnach
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Just throwing this out there: if you happen to need to match against more than one string, for example abc and def, you can combine two comprehensions as follows:
matchers = ['abc','def']
matching = [s for s in my_list if any[xs in s for xs in matchers]]
Output:
['abc-123', 'def-456', 'abc-456']
answered Aug 3, 2014 at 6:00
fantabolousfantabolous
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Use filter to get all the elements that have 'abc':
>>> xs = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
>>> list[filter[lambda x: 'abc' in x, xs]]
['abc-123', 'abc-456']
One can also use a list comprehension:
>>> [x for x in xs if 'abc' in x]
Mateen Ulhaq
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answered Jan 30, 2011 at 13:34
MAKMAK
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If you just need to know if 'abc' is in one of the items, this is the shortest way:
if 'abc' in str[my_list]:
Note: this assumes 'abc' is an alphanumeric text. Do not use it if 'abc' could be just a special character [i.e. []', ].
answered Apr 13, 2016 at 8:19
RogerSRogerS
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This is quite an old question, but I offer this answer because the previous answers do not cope with items in the list that are not strings [or some kind of iterable object]. Such items would cause the entire list comprehension to fail with an exception.
To gracefully deal with such items in the list by skipping the non-iterable items, use the following:
[el for el in lst if isinstance[el, collections.Iterable] and [st in el]]
then, with such a list:
lst = [None, 'abc-123', 'def-456', 'ghi-789', 'abc-456', 123]
st = 'abc'
you will still get the matching items [['abc-123', 'abc-456']]
The test for iterable may not be the best. Got it from here: In Python, how do I determine if an object is iterable?
answered Oct 20, 2011 at 13:24
Robert MuilRobert Muil
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x = 'aaa'
L = ['aaa-12', 'bbbaaa', 'cccaa']
res = [y for y in L if x in y]
jamylak
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answered Jan 30, 2011 at 13:31
MariyMariy
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for item in my_list:
if item.find["abc"] != -1:
print item
jamylak
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answered Jan 30, 2011 at 13:38
RubyconRubycon
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any['abc' in item for item in mylist]
answered Jan 30, 2011 at 13:34
ImranImran
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I am new to Python. I got the code below working and made it easy to understand:
my_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
for item in my_list:
if 'abc' in item:
print[item]
answered Apr 7, 2018 at 7:52
Amol ManthalkarAmol Manthalkar
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Use the __contains__[] method of Pythons string class.:
a = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
for i in a:
if i.__contains__["abc"] :
print[i, " is containing"]
kalehmann
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answered Feb 8, 2019 at 16:37
Harsh LodhiHarsh Lodhi
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If you want to get list of data for multiple substrings
you can change it this way
some_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
# select element where "abc" or "ghi" is included
find_1 = "abc"
find_2 = "ghi"
result = [element for element in some_list if find_1 in element or find_2 in element]
# Output ['abc-123', 'ghi-789', 'abc-456']
answered Jul 14, 2020 at 2:43
I needed the list indices that correspond to a match as follows:
lst=['abc-123', 'def-456', 'ghi-789', 'abc-456']
[n for n, x in enumerate[lst] if 'abc' in x]
output
[0, 3]
answered Jan 5, 2020 at 19:02
Grant ShannonGrant Shannon
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mylist=['abc','def','ghi','abc']
pattern=re.compile[r'abc']
pattern.findall[mylist]
Bugs
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answered Jul 4, 2018 at 13:32
3
Adding nan to list, and the below works for me:
some_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456',np.nan]
any[[i for i in [x for x in some_list if str[x] != 'nan'] if "abc" in i]]
answered Feb 18, 2021 at 2:38
Sam SSam S
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my_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
for item in my_list:
if [item.find['abc']] != -1:
print ['Found at ', item]
answered Mar 16, 2018 at 9:14
I did a search, which requires you to input a certain value, then it will look for a value from the list which contains your input:
my_list = ['abc-123',
'def-456',
'ghi-789',
'abc-456'
]
imp = raw_input['Search item: ']
for items in my_list:
val = items
if any[imp in val for items in my_list]:
print[items]
Try searching for 'abc'.
answered Jan 26, 2019 at 2:44
def find_dog[new_ls]:
splt = new_ls.split[]
if 'dog' in splt:
print["True"]
else:
print['False']
find_dog["Is there a dog here?"]
4b0
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answered Jul 18, 2019 at 8:22
Question : Give the informations of abc
a = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
aa = [ string for string in a if "abc" in string]
print[aa]
Output => ['abc-123', 'abc-456']
answered Jun 16, 2018 at 10:52