Kiểm tra xem số đó có phải là số lượng nhiều trong Python hay không
Đưa ra một đầu vào số nguyên dưới dạng số, mục tiêu là kiểm tra xem số nguyên đã cho có phải là số phong phú hay không. Do đó, chúng tôi sẽ viết một chương trình để kiểm tra xem số đó có phải là số lượng phong phú trong ngôn ngữ Python hay không.
Example Input : 21 Output : It's not an Abundant Number.
Kiểm tra xem số đó có phải là số lượng nhiều trong ngôn ngữ Python hay không
Cho một số nguyên nhập mục tiêu là kiểm tra xem số nguyên đã cho có phải là một số lượng nhiều hay không. Để làm như vậy, chúng tôi sẽ sử dụng Loop để tìm các yếu tố của số ngoại trừ chính số và tổng số tất cả chúng. Chúng tôi sẽ kiểm tra xem số này thấp hơn hay lớn hơn tổng. Đối với một số được phân loại là phong phú, tổng của các yếu tố của nó phải lớn hơn chính số. Dưới đây là phương pháp mà chúng tôi sẽ sử dụng để kiểm tra xem số đó có phải là số lượng nhiều trong ngôn ngữ Python hay không,
- Phương pháp 1: Sử dụng phạm vi cho đến khi số Using Range until Number
- Phương pháp 2: Sử dụng phạm vi cho đến khi SQRT [số] Using Range until Sqrt[ Number ]
Chúng tôi sẽ thảo luận về các phương pháp được đề cập ở trên một cách chi tiết trong các phần sắp tới. Hãy kiểm tra hộp màu xanh được đưa ra dưới đây để hiểu rõ hơn về các câu hỏi được đề cập ở trên.
Số số phong phú nhỏ hơn tổng của tất cả các yếu tố của nó ngoại trừ chính số được gọi là một số lượng phong phú. Hãy thử và hiểu khái niệm tốt hơn bằng cách sử dụng một ví dụ A Number that is smaller than the sum of all it's factors except the number itself is known as an Abundant number.
Let's try and understand the concept better using an example
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.Chúng tôi sẽ thảo luận về cách kiểm tra nó trong các phần sắp tới.
Phương pháp 1: Sử dụng phạm vi cho đến khi số Using Range until Number
Phương pháp 2: Sử dụng phạm vi cho đến khi SQRT [số]
Chúng tôi sẽ thảo luận về các phương pháp được đề cập ở trên một cách chi tiết trong các phần sắp tới. Hãy kiểm tra hộp màu xanh được đưa ra dưới đây để hiểu rõ hơn về các câu hỏi được đề cập ở trên.
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']
Số số phong phú nhỏ hơn tổng của tất cả các yếu tố của nó ngoại trừ chính số được gọi là một số lượng phong phú. Hãy thử và hiểu khái niệm tốt hơn bằng cách sử dụng một ví dụ
12 is Abundant Number
Phương pháp 2: Sử dụng phạm vi cho đến khi SQRT [số] Using Range until Sqrt[ Number ]
Phương pháp 2: Sử dụng phạm vi cho đến khi SQRT [số]
Chúng tôi sẽ thảo luận về các phương pháp được đề cập ở trên một cách chi tiết trong các phần sắp tới. Hãy kiểm tra hộp màu xanh được đưa ra dưới đây để hiểu rõ hơn về các câu hỏi được đề cập ở trên.
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]
Số số phong phú nhỏ hơn tổng của tất cả các yếu tố của nó ngoại trừ chính số được gọi là một số lượng phong phú. Hãy thử và hiểu khái niệm tốt hơn bằng cách sử dụng một ví dụ
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.Chúng tôi sẽ thảo luận về cách kiểm tra nó trong các phần sắp tới.
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Một số N được cho là một số phong phú nếu tổng của tất cả các giao diện thích hợp của số được ký hiệu theo tổng [n] lớn hơn giá trị của số n. Và sự khác biệt giữa hai giá trị này được gọi là phong phú. & Nbsp; về mặt toán học, nếu điều kiện bên dưới giữ số được cho là một số lượng phong phú:abundance.
Mathematically, if the below condition holds the number is said to be an Abundant number:
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n
Đưa ra một số n, nhiệm vụ của chúng tôi là tìm số này có phải là số phong phú hay không. , 60, 66, .. & nbsp;
The first few Abundant Numbers are: 12, 18, 20,
24, 30, 36, 40, 42, 48, 54, 56, 60, 66 …..
Examples:
Input: 21 Output: NO Input: 12 Output: YES Input: 17 Output: NO
Phương pháp 1: Một giải pháp đơn giản là lặp lại tất cả các số từ 1 đến N-1 và kiểm tra xem số có chia N và tính tổng. Kiểm tra xem tổng này có lớn hơn N hay không.A Simple solution is to iterate all the numbers from 1 to n-1 and check if the number divides n and calculate the sum. Check if this sum is greater than n or not.
C++
#include
using
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.0
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.1
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.2
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.3
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.5
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.9
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']2
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.4
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']4
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']6
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']7
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']9
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
12 is Abundant Number1
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
12 is Abundant Number1
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']6
12 is Abundant Number6
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
12 is Abundant Number8
12 is Abundant Number9
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]0
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
12 is Abundant Number1
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
12 is Abundant Number8
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]8
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]0
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
12 is Abundant Number1
12 is Abundant Number1
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.4
12 is Abundant Number4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']6
12 is Abundant Number8
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n0
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n1
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n2
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]0
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
12 is Abundant Number1
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
12 is Abundant Number8
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]8
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]0
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]0
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
12 is Abundant Number1
12 is Abundant Number1
Example
Input : Number = 12
Output : Yes, It's an Abundant Number
Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself.
Now the sum of the factors except the number itself is :
1 + 2 + 3 + 4 + 6 = 16
as the number 16>12 , the number itself.
It's an abundant number.
4 12 is Abundant Number
4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']6
12 is Abundant Number8
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n0
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n1
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n2
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n0
Input: 21 Output: NO Input: 12 Output: YES Input: 17 Output: NO2
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n2
Java
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
Input: 21 Output: NO Input: 12 Output: YES Input: 17 Output: NO9
#include
0Input: 21 Output: NO Input: 12 Output: YES Input: 17 Output: NO9
#include
2#include
3 #include
4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.11
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']9
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
12 is Abundant Number1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
12 is Abundant Number1
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
#include
6 #include
7 #include
8 Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.3
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.5
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.4
using
6using
7import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]0
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
12 is Abundant Number1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']22
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.03
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.044____105
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']6
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.08
using
7Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.10
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
12 is Abundant Number1
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
12 is Abundant Number1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']6
12 is Abundant Number6
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
12 is Abundant Number8
12 is Abundant Number9
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]0
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
12 is Abundant Number1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']22
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.03
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.044____105
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.50
Input: 21 Output: NO Input: 12 Output: YES Input: 17 Output: NO2
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.52
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
12 is Abundant Number1
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
12 is Abundant Number1
12 is Abundant Number1
Python3
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']6
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.08
using
7Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.10
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']6
12 is Abundant Number6
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
12 is Abundant Number8
12 is Abundant Number9
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]0
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
12 is Abundant Number8
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]8
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]0
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
#include
6 #include
7 Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.40
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.41
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']6
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.46
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.47
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.48
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.88
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.97
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']2
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']06
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']00
C#
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.50
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n1
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.52
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n0
Input: 21 Output: NO Input: 12 Output: YES Input: 17 Output: NO2
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n2
Java
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
Input: 21 Output: NO Input: 12 Output: YES Input: 17 Output: NO9
#include
0Input: 21 Output: NO Input: 12 Output: YES Input: 17 Output: NO9
#include
2#include
3 #include
4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.11
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']9
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
12 is Abundant Number1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
12 is Abundant Number1
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
#include
6 #include
7 #include
8 Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.3
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.5
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.4
using
6using
7import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]0
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
12 is Abundant Number1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']22
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.03
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.044____105
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']6
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.08
using
7Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.10
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
12 is Abundant Number1
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
12 is Abundant Number1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']6
12 is Abundant Number6
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
12 is Abundant Number8
12 is Abundant Number9
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]0
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']71
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n1
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.52
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
12 is Abundant Number1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']22
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.03
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.044____105
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']71
Input: 21 Output: NO Input: 12 Output: YES Input: 17 Output: NO2
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.52
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
12 is Abundant Number1
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
12 is Abundant Number1
12 is Abundant Number1
n = 12
sum=1 # 1 can divide any number
for i in range[2,n]:
if[n%i==0]: #if number is divisible by i add the number
sum=sum+i
if[sum>n]:
print[n,'is Abundant Number']
else:
print[n,'is not Abundant Number']
8n = 12
sum=1 # 1 can divide any number
for i in range[2,n]:
if[n%i==0]: #if number is divisible by i add the number
sum=sum+i
if[sum>n]:
print[n,'is Abundant Number']
else:
print[n,'is not Abundant Number']
6 Example
Input : Number = 12
Output : Yes, It's an Abundant Number
Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself.
Now the sum of the factors except the number itself is :
1 + 2 + 3 + 4 + 6 = 16
as the number 16>12 , the number itself.
It's an abundant number.
08using
7Example
Input : Number = 12
Output : Yes, It's an Abundant Number
Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself.
Now the sum of the factors except the number itself is :
1 + 2 + 3 + 4 + 6 = 16
as the number 16>12 , the number itself.
It's an abundant number.
10
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']88
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']6
12 is Abundant Number6
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']93
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
12 is Abundant Number8
12 is Abundant Number9
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]0
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
12 is Abundant Number00
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']9
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.11
12 is Abundant Number1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
12 is Abundant Number1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
12 is Abundant Number8
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]8
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]0
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
#include
6 #include
7 Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.40
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.41
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
12 is Abundant Number1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']6
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.46
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.47
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.48
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.50
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n1
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.52
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
12 is Abundant Number1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
12 is Abundant Number1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
12 is Abundant Number8
12 is Abundant Number9
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]0
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
12 is Abundant Number1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']22
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.03
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.044____105
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
12 is Abundant Number30
Input: 21 Output: NO Input: 12 Output: YES Input: 17 Output: NO2
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.52
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
12 is Abundant Number1
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
12 is Abundant Number45
n = 12
sum=1 # 1 can divide any number
for i in range[2,n]:
if[n%i==0]: #if number is divisible by i add the number
sum=sum+i
if[sum>n]:
print[n,'is Abundant Number']
else:
print[n,'is not Abundant Number']
8n = 12
sum=1 # 1 can divide any number
for i in range[2,n]:
if[n%i==0]: #if number is divisible by i add the number
sum=sum+i
if[sum>n]:
print[n,'is Abundant Number']
else:
print[n,'is not Abundant Number']
6 Example
Input : Number = 12
Output : Yes, It's an Abundant Number
Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself.
Now the sum of the factors except the number itself is :
1 + 2 + 3 + 4 + 6 = 16
as the number 16>12 , the number itself.
It's an abundant number.
08using
7Example
Input : Number = 12
Output : Yes, It's an Abundant Number
Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself.
Now the sum of the factors except the number itself is :
1 + 2 + 3 + 4 + 6 = 16
as the number 16>12 , the number itself.
It's an abundant number.
10
12 is Abundant Number46
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
12 is Abundant Number48
12 is Abundant Number49
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
12 is Abundant Number51
12 is Abundant Number52
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']6
12 is Abundant Number6
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
12 is Abundant Number8
12 is Abundant Number9
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]0
12 is Abundant Number00
12 is Abundant Number51
12 is Abundant Number73
12 is Abundant Number56
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]0
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.11
12 is Abundant Number1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
12 is Abundant Number1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']6
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']22____351
12 is Abundant Number84
12 is Abundant Number48
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.10
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.11
12 is Abundant Number88
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.99
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]0
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
12 is Abundant Number1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.11
12 is Abundant Number88
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']06
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]0
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
12 is Abundant Number1
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]02
Độ phức tạp về thời gian: O [n] cho một số nhất định N.AUXILIARITY: O [1]O[n] for a given number n.
Auxiliary Space: O[1]
Giải pháp được tối ưu hóa: Nếu chúng ta quan sát cẩn thận, các ước số của số N có mặt theo cặp. Ví dụ: nếu n = 100, thì tất cả các cặp chia đều là: [1.100], [2,50], [4,25], [5,20], [10,10] bằng cách sử dụng thực tế này, chúng ta có thể tăng tốc độ chương trình. Trong khi kiểm tra các ước số, chúng tôi sẽ phải cẩn thận nếu có hai ước số bằng nhau như trong trường hợp của [10, 10]. Trong trường hợp như vậy, chúng tôi sẽ chỉ lấy một trong số chúng trong tính toán tổng. & NBSP; trừ số n từ tổng của tất cả các giao diện để có được tổng số các giao hàng thích hợp. & NBSP;
If we observe carefully, the divisors of the number n are present in
pairs. For example if n = 100, then all the pairs of divisors are: [1,100], [2,50], [4,25], [5,20], [10,10]
Using this fact we can speed up our program. While checking divisors we will have to be careful if there are two equal divisors as in the case of [10, 10]. In such a case, we will take only one of them in the calculation of the sum.
Subtract the number n from the sum of all divisors to get the sum of proper divisors.
C++
#include
using
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.0
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.1
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.4
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]08
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.5
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.9
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']2
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.4
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]19
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]20
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]21
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']6
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]26
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']6
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]31
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.11
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]33
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]4
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.11
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]33
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.11
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]41
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
12 is Abundant Number1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
12 is Abundant Number1
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
12 is Abundant Number1
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]49
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
12 is Abundant Number8
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]52
12 is Abundant Number1
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.2
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]55
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.5
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
12 is Abundant Number8
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]61
12 is Abundant Number1
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.4
12 is Abundant Number4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]67
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]68
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]69
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]70
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]0
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]73
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]68
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]69
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]70
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]0
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
12 is Abundant Number8
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]80
12 is Abundant Number1
Java
Input: 21 Output: NO Input: 12 Output: YES Input: 17 Output: NO9
#include
0Input: 21 Output: NO Input: 12 Output: YES Input: 17 Output: NO9
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]85
#include
3
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]87
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
#include
7 Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.4
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]08
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.5
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.4
using
6using
7import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]0
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']22
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.4
12 is Abundant Number05
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.044____507
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']6
12 is Abundant Number12
using
7n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']00
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.11
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']6
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]31
12 is Abundant Number20
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]33
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.11
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.11
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
12 is Abundant Number20
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]33
12 is Abundant Number20
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]41
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.11
12 is Abundant Number1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
12 is Abundant Number1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
12 is Abundant Number1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]49
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
12 is Abundant Number8
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]52
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
12 is Abundant Number1
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
#include
7 #include
8 import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]55
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.5
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
12 is Abundant Number51
12 is Abundant Number8
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]61
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
12 is Abundant Number1
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
#include
6 #include
7 Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.40
12 is Abundant Number60
12 is Abundant Number61
12 is Abundant Number62
12 is Abundant Number63
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
12 is Abundant Number51
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']6
12 is Abundant Number68
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.47
12 is Abundant Number70
12 is Abundant Number71
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.50
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n1
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.52
12 is Abundant Number51
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]4
12 is Abundant Number71
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.50
Input: 21 Output: NO Input: 12 Output: YES Input: 17 Output: NO2
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.52
12 is Abundant Number51
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']6
12 is Abundant Number68
12 is Abundant Number84
12 is Abundant Number70
12 is Abundant Number71
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.50
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n1
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.52
12 is Abundant Number51
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]4
12 is Abundant Number71
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.50
Input: 21 Output: NO Input: 12 Output: YES Input: 17 Output: NO2
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.52
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
12 is Abundant Number1
12 is Abundant Number1
Python3
Input: 21 Output: NO Input: 12 Output: YES Input: 17 Output: NO9
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n00
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n01
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n02
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n04
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.68
using
7Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.74
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.68
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.04
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n12
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n13
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.68
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n15
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']6
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n18
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.83__
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']6
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n18
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n28
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n28
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.74
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.68
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.68
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n33
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.11
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n04
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.68
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n04
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.91
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.93
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]4
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n42
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.11
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n04
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.68
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n04
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.91
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.93
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]4
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n42
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.11
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n04
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.68
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n04
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.91
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n54
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n28
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n28
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n57
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.74
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.68
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.74
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.91
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.04
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n04
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.68
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n04
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n68
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n18
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
12 is Abundant Number8
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n04
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n01
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n74
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']6
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n77
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
12 is Abundant Number8
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.04
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.88
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
12 is Abundant Number8
using
7Các
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.97
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']2
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']00
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.88
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.97
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']2
Input: 21 Output: NO Input: 12 Output: YES Input: 17 Output: NO2
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']00
Các
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.97
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']2
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']00
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.88
C#
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.97
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']2
Input: 21 Output: NO Input: 12 Output: YES Input: 17 Output: NO2
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']00
Các
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
#include
7 Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.4
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]08
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.5
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.9
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']2
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.4
Input: 21 Output: NO Input: 12 Output: YES Input: 17 Output: NO46
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']6
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']7
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.11
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']6
Input: 21 Output: NO Input: 12 Output: YES Input: 17 Output: NO52
12 is Abundant Number00
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]33
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.11
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.11
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
12 is Abundant Number00
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]33
12 is Abundant Number00
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]41
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.11
12 is Abundant Number1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
12 is Abundant Number1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
12 is Abundant Number1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]49
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
12 is Abundant Number8
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]52
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
12 is Abundant Number1
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
#include
7 Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.2
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]55
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.4
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.5
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
12 is Abundant Number8
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]61
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
12 is Abundant Number1
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
#include
6 #include
7 Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.40
Input: 21 Output: NO Input: 12 Output: YES Input: 17 Output: NO93
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']6
Input: 21 Output: NO Input: 12 Output: YES Input: 17 Output: NO98
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']71
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n1
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.52
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]4
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']71
Input: 21 Output: NO Input: 12 Output: YES Input: 17 Output: NO2
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.52
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']6
#include
11n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']71
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n1
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.52
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]4
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']71
Input: 21 Output: NO Input: 12 Output: YES Input: 17 Output: NO2
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.52
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
12 is Abundant Number1
12 is Abundant Number1
PHP
12 is Abundant Number46
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']90
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]08
12 is Abundant Number48
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']00
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
#include
32 #include
33Is
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']6
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']22
12 is Abundant Number48
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']6
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']2
12 is Abundant Number48
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.11
#include
32 #include
67#include
32 #include
6912 is Abundant Number56
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]0
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]4
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.11
#include
32 #include
67#include
32 #include
6912 is Abundant Number56
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]0
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.11
#include
32 #include
67#include
32 #include
8712 is Abundant Number48
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
12 is Abundant Number1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
12 is Abundant Number1
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
12 is Abundant Number1
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
#include
32 #include
67#include
32 using
0212 is Abundant Number48
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]0
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
12 is Abundant Number8
#include
32import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]0
12 is Abundant Number1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']90
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]55
12 is Abundant Number48
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']00
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
12 is Abundant Number8
using
1712 is Abundant Number48
using
1912 is Abundant Number48
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.52
12 is Abundant Number1
using
23 using
24
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]68
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n42
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]70
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]0
12 is Abundant Number88
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']2
using
23Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.52
using
23 using
34
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]68
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n42
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]70
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]0
12 is Abundant Number88
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']2
using
23Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.52
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]02
JavaScript
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']88
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']90
using
46Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']93
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']1
using
52Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']6
using
57n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']6
Input: 21 Output: NO Input: 12 Output: YES Input: 17 Output: NO52
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.11
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]33
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]4
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.11
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]33
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.11
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]41
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']8
12 is Abundant Number1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']5
12 is Abundant Number1
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
12 is Abundant Number1
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]49
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
12 is Abundant Number8
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]52
12 is Abundant Number1
n = 12 sum=1 # 1 can divide any number for i in range[2,n]: if[n%i==0]: #if number is divisible by i add the number sum=sum+i if[sum>n]: print[n,'is Abundant Number'] else: print[n,'is not Abundant Number']90
using
86Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.6
Example Input : Number = 12 Output : Yes, It's an Abundant Number Explanation : The Factors for the number 12 are, 1, 2, 3, 4 and 6. We don't want to include the number itself. Now the sum of the factors except the number itself is : 1 + 2 + 3 + 4 + 6 = 16 as the number 16>12 , the number itself. It's an abundant number.7
12 is Abundant Number8
import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]61
12 is Abundant Number1
using
92using
93
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n42
using
95import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]0
using
97
using
98using
93
sum[n]> n abundance = sum[n] - n sum[n]: aliquot sum - The sum of all proper divisors of n42
using
95import math n = 12 sum=1 # 1 can divide any number i=2 while[in]: print[n,"is Abundant Number"] else: print[n,"is not Abundant Number"]0
using
97
12 is Abundant Number45
Độ phức tạp về thời gian: O [sqrt [n]] & nbsp; không gian phụ trợ: O [1] O[sqrt[n]]
Auxiliary Space: O[1]
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//en.wikipedia.org/wiki/Abundant_number
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