Tôi cần một chương trình cho phép ba số được nhập và đầu ra nếu chúng có thể tạo thành một bộ ba Pythagore [ví dụ: a^2 + b^2 = c^2 / hoặc / 3^2 + 4^2 = 5^].
Tôi có một giải pháp, nhưng tôi cảm thấy như nó thực sự không hiệu quả và tôi đã tự hỏi nếu có một giải pháp ngắn hơn, tốt hơn có sẵn?
Giải pháp của tôi cho đến nay:
nums = []
for num in range[0,3]:
nums.append[int[input["Enter a number"]]]
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
// Is a pythagorean triple
Vân vân..
Đã hỏi ngày 12 tháng 3 năm 2017 lúc 20:31Mar 12, 2017 at 20:31
3
Chỉ cần sắp xếp nums
. Sau đó, bạn sẽ chỉ phải thực hiện một kiểm tra:
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
Đã trả lời ngày 12 tháng 3 năm 2017 lúc 20:41Mar 12, 2017 at 20:41
MaratmaratMarat
14.2k2 Huy hiệu vàng37 Huy hiệu bạc45 Huy hiệu đồng2 gold badges37 silver badges45 bronze badges
Một bộ ba Pythagore là một tập hợp ba số nguyên dương A, B và C sao cho A2 + B2 = C2. Đưa ra một giới hạn, tạo ra tất cả các bộ ba Pythagore với các giá trị nhỏ hơn giới hạn đã cho.
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 20
Một giải pháp đơn giản là tạo ra các bộ ba này nhỏ hơn giới hạn được cho bằng cách sử dụng ba vòng lồng nhau. Đối với mỗi bộ ba, hãy kiểm tra xem điều kiện Pythagore có đúng không, nếu đúng, sau đó in bộ ba. Độ phức tạp thời gian của giải pháp này là O [giới hạn3] trong đó ‘giới hạn được đưa ra giới hạn.Simple Solution is to generate these triplets smaller than given limit using three nested loop. For every triplet, check if Pythagorean condition is true, if true, then print the triplet. Time complexity of this solution is O[limit3] where ‘limit’ is given limit.
Một giải pháp hiệu quả có thể in tất cả các bộ ba trong thời gian O [k] trong đó k là số lượng ba bản in. Ý tưởng là sử dụng mối quan hệ tổng vuông của bộ ba Pythagore, tức là, việc bổ sung các hình vuông của A và B bằng với bình phương C, chúng ta có thể viết số này theo m và n sao cho, & nbsp; & nbsp;Efficient Solution can print all triplets in O[k] time where k is number of triplets printed. The idea is to use square sum relation of Pythagorean triplet, i.e., addition of squares of a and b is equal to square of c, we can write these number in terms of m and n such that,
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n2
Chúng ta có thể thấy rằng A2 + B2 = C2, vì vậy thay vì lặp lại cho A, B và C, chúng ta có thể lặp lại cho M và N và có thể tạo các bộ ba này. & NBSP;
Dưới đây là việc thực hiện ý tưởng trên: & nbsp; & nbsp;
C++
#include
void
pythagoreanTriplets[
int
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
0nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
1nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
2int
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
4nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
2int
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
7nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
2nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
9 Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 200
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 201
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 202
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 203
int
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 205
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 206
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 207
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 206
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 209
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 206
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n21
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 206
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n23
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n24
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n25
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n26
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n27
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 206
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n29
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 203
3 4 5 8 6 10 5 12 13 15 8 17 12 16 201
3 4 5 8 6 10 5 12 13 15 8 17 12 16 202
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 201
3 4 5 8 6 10 5 12 13 15 8 17 12 16 204
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 201
3 4 5 8 6 10 5 12 13 15 8 17 12 16 206
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
23 4 5 8 6 10 5 12 13 15 8 17 12 16 204
3 4 5 8 6 10 5 12 13 15 8 17 12 16 204
int
nums
1
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
1nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
2int
nums
5nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
2nums
7nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
2nums
9 #include
03 4 5 8 6 10 5 12 13 15 8 17 12 16 204
Java
#include
2 #include
3
#include
2 #include
5
#include
6 #include
7
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
2#include
9 void
pythagoreanTriplets[
int
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
0nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
2nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
1Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 201
int
void
8void
9a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n27
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 201
int
pythagoreanTriplets[
3pythagoreanTriplets[
4a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n27
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 201
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
9 Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 200
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 206
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 202
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 203
int
int
3int
4int
5a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n25
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 207
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n25
int
9pythagoreanTriplets[
4 nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
01a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n25
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n21
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n25
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n23
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n24
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
07a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n26
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n27
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n25
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
11nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
12 nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
13nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
12 nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
15Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 206
3 4 5 8 6 10 5 12 13 15 8 17 12 16 204
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 206
3 4 5 8 6 10 5 12 13 15 8 17 12 16 206
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 201
3 4 5 8 6 10 5 12 13 15 8 17 12 16 204
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
23 4 5 8 6 10 5 12 13 15 8 17 12 16 204
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
2nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
25 #include
9 void
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
28nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
2nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
1Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 201
int
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
33nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
34a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n27
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 201
nums
7nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
23 4 5 8 6 10 5 12 13 15 8 17 12 16 204
3 4 5 8 6 10 5 12 13 15 8 17 12 16 204
Python3
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
41 nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
42nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
2nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
44nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
45 void
9nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
47pythagoreanTriplets[
4nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
2nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
9 nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
51Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 201
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 202
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
54nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
55 nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
56Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 203
int
4nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
59Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 206
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
61nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
45 nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
63nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
64 nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
63nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
66 nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
54__Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 206
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
71nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
45 pythagoreanTriplets[
4 nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
64 nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
63nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
64 nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
69Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 206
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
79nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
45 nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
63nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
64 nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
63nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
84 nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
54__Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 206
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n23
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
90a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n25
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n26
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 206
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
94nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
95Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 201
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
63nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
45 nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
63nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
84 int
4a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n23
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 2003
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
45nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
45 Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 2006
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 2007
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
2Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 2009
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
45 nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
34nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
2Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 2013
C#
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 2014
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 2015
#include
6 #include
7
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
2#include
9 void
pythagoreanTriplets[
int
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
0nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
2nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
1Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 201
int
void
8void
9a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n27
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 201
int
pythagoreanTriplets[
3pythagoreanTriplets[
4a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n27
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 201
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
9 Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 200
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 206
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 202
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 203
int
int
3int
4int
5Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 206
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
1a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n25
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 207
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n25
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 209
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n25
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n21
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n25
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n23
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n24
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
07a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n26
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n27
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n25
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 2055
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
12a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n25
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
11nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
12 nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
13nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
12 nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
15Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 206
3 4 5 8 6 10 5 12 13 15 8 17 12 16 204
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 206
3 4 5 8 6 10 5 12 13 15 8 17 12 16 206
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
2nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
25 #include
9 void
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
28nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
23 4 5 8 6 10 5 12 13 15 8 17 12 16 204
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
2nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
1nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
2nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
1Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 201
int
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
33nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
34a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n27
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 201
nums
7nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
23 4 5 8 6 10 5 12 13 15 8 17 12 16 204
3 4 5 8 6 10 5 12 13 15 8 17 12 16 204
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
41 nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
42
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 2084
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
2nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
44nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
45 void
9nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
47pythagoreanTriplets[
4nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
1nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
2Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 2091
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n27
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
2Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 2094
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n27
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
2Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 2097
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 2098
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
2nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
9 nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
51Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 201
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 202
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
54nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
55 nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
56Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 203
int
4nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
59
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
2nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
1Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 206
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
61nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
45 nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
63nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
64 nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
63nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
66 nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
54__Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 201
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
1Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 206
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
71nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
45 pythagoreanTriplets[
4 nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
64 nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
63nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
64 nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
69Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 206
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
79nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
45 nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
63nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
64 nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
63nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
84 nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
54__Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 206
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n23
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
90Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 201
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
63nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
45 nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
63nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
84 int
4a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n23
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 2003
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
45nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
45 Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 2006
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 2007
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
2Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 2009
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
45 nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
34Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 201
3 4 5 8 6 10 5 12 13 15 8 17 12 16 204
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 201
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n200
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n281
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
23 4 5 8 6 10 5 12 13 15 8 17 12 16 204
3 4 5 8 6 10 5 12 13 15 8 17 12 16 204
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 2014
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 2015
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
2pythagoreanTriplets[
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 2087
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n291
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n292
Input : limit = 20
Output : 3 4 5
8 6 10
5 12 13
15 8 17
12 16 20
1int
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
4
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n293
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 201
int
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
7nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
1nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
2a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n298
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
23 4 5 8 6 10 5 12 13 15 8 17 12 16 2000
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 206
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 202
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 203
int
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 2039
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
2nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
1Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 201
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 202
3 4 5 8 6 10 5 12 13 15 8 17 12 16 2008
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 201
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
1Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 206
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 207
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 206
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 209
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 206
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n21
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 206
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n23
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n24
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n25
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n26
a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n27
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 201
int
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
33nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
34a = m2 - n2 b = 2 * m * n c = m2 + n2 because, a2 = m4 + n4 – 2 * m2 * n2 b2 = 4 * m2 * n2 c2 = m4 + n4 + 2* m2 * n27
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
41 nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
42Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 201
3 4 5 8 6 10 5 12 13 15 8 17 12 16 204
Input : limit = 20 Output : 3 4 5 8 6 10 5 12 13 15 8 17 12 16 201
3 4 5 8 6 10 5 12 13 15 8 17 12 16 206
nums.sort[] # now nums[2] is the largest element
if [[nums[0] ** 2] + [nums[1] ** 2] == [nums[2] ** 2]]:
print "It is" # or whatever
# no more checks needed
23 4 5 8 6 10 5 12 13 15 8 17 12 16 204
3 4 5 8 6 10 5 12 13 15 8 17 12 16 204
3 4 5 8 6 10 5 12 13 15 8 17 12 16 2039
nums
7
3 4 5 8 6 10 5 12 13 15 8 17 12 16 2041
Đầu ra
3 4 5 8 6 10 5 12 13 15 8 17 12 16 20
Độ phức tạp về thời gian của phương pháp này là O [k] trong đó k là số lượng ba lần được in cho một giới hạn nhất định [chúng tôi chỉ lặp cho M và N và mọi lần lặp lại đều in một bộ ba] biến of this approach is O[k] where k is number of triplets printed for a given limit [We iterate for m and n only and every iteration prints a triplet]
Auxiliary space: O[1] as it is using constant space for variables
Lưu ý: Phương pháp trên không tạo ra tất cả các bộ ba nhỏ hơn một giới hạn nhất định. Ví dụ: 9 12 12 15, đó là bộ ba hợp lệ không được in bằng phương pháp trên. Cảm ơn Sid Agrawal đã chỉ ra điều này. The above method doesn’t generate all triplets smaller than a given limit. For example “9 12 15” which is a valid triplet is not printed by above method. Thanks to Sid Agrawal for pointing this out.
References:
//en.wikipedia.org/wiki/Formulas_for_generating_Pythagorean_triples
Bài viết này được đóng góp bởi Utkarsh Trivingi. Vui lòng viết nhận xét nếu bạn tìm thấy bất cứ điều gì không chính xác, hoặc bạn muốn chia sẻ thêm thông tin về chủ đề được thảo luận ở trên.Utkarsh Trivedi. Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.