Python Tuple: Tập thể dục-9 với giải pháp
Viết một chương trình Python để tìm các mục lặp đi lặp lại của một tuple.
Giải pháp mẫu:-:-
Mã Python:
#create a tuple
tuplex = 2, 4, 5, 6, 2, 3, 4, 4, 7
print[tuplex]
#return the number of times it appears in the tuple.
count = tuplex.count[4]
print[count]
Đầu ra mẫu:
[2, 4, 5, 6, 2, 3, 4, 4, 7] 3
Trình bày bằng hình ảnh:
Flowchart:
Trực quan hóa thực thi mã Python:
Công cụ sau đây trực quan hóa những gì máy tính đang làm từng bước khi nó thực hiện chương trình đã nói:
Trình chỉnh sửa mã Python:
Có một cách khác để giải quyết giải pháp này? Đóng góp mã của bạn [và nhận xét] thông qua Disqus.
Trước đây: Viết một chương trình Python để tạo dấu hai chấm của một tuple. Write a Python program to create the colon of a tuple.
Next: Write a Python program to check whether an element
exists within a tuple.
Python: Lời khuyên trong ngày
Cấu trúc Deques [Deques là một khái quát của các ngăn xếp và hàng đợi]:
>>> import collections >>> Q = collections.deque[] >>> Q.append[1] >>> Q.appendleft[2] >>> Q.extend[[3, 4]] >>> Q.extendleft[[5, 6]] >>> Q deque[[6, 5, 2, 1, 3, 4]] >>> Q.pop[] 4 >>> Q.popleft[] 6 >>> Q deque[[5, 2, 1, 3]] >>> Q.rotate[3] >>> Q deque[[2, 1, 3, 5]] >>> Q.rotate[-3] >>> Q deque[[5, 2, 1, 3]] >>> last_three = collections.deque[maxlen=3] >>> for i in range[4]: ... last_three.append[i] ... print ', '.join[str[x] for x in last_three] ... 0 0, 1 0, 1, 2 1, 2, 3 2, 3, 4
Cách pythonic để làm điều này là sử dụng bộ sưu tập.
>>> from collections import Counter
>>> t = [1,1,1,1,1,2,2,2,3,3,4,5,6,7,8,9]
>>> c = Counter[t]
>>> c
Counter[{1: 5, 2: 3, 3: 2, 4: 1, 5: 1, 6: 1, 7: 1, 8: 1, 9: 1}]
Counter trả về một đối tượng giống như dict có thể được lặp đi lặp lại, cùng với các hoạt động khác.
Nhiều lần, trong khi làm việc với các bộ dữ liệu Python, chúng ta có thể gặp vấn đề khi loại bỏ các bản sao. Đây là một vấn đề rất phổ biến và có thể xảy ra trong bất kỳ hình thức thiết lập lập trình nào, có thể là lập trình thường xuyên hoặc phát triển web. Hãy để thảo luận về những cách nhất định trong đó nhiệm vụ này có thể được thực hiện. & NBSP;
Phương thức số 1: Sử dụng Set [] + Tuple [] Đây là cách thẳng tiến nhất để loại bỏ các bản sao. Trong đó, chúng tôi chuyển đổi tuple thành một tập hợp, loại bỏ các bản sao và sau đó chuyển đổi nó lại bằng Tuple []. & NBSP; This is the most straight forward way to remove duplicates. In this, we convert the tuple to a set, removing duplicates and then converting it back again using tuple[].
Python3
Các
>>> import collections >>> Q = collections.deque[] >>> Q.append[1] >>> Q.appendleft[2] >>> Q.extend[[3, 4]] >>> Q.extendleft[[5, 6]] >>> Q deque[[6, 5, 2, 1, 3, 4]] >>> Q.pop[] 4 >>> Q.popleft[] 6 >>> Q deque[[5, 2, 1, 3]] >>> Q.rotate[3] >>> Q deque[[2, 1, 3, 5]] >>> Q.rotate[-3] >>> Q deque[[5, 2, 1, 3]] >>> last_three = collections.deque[maxlen=3] >>> for i in range[4]: ... last_three.append[i] ... print ', '.join[str[x] for x in last_three] ... 0 0, 1 0, 1, 2 1, 2, 3 2, 3, 48
>>> import collections >>> Q = collections.deque[] >>> Q.append[1] >>> Q.appendleft[2] >>> Q.extend[[3, 4]] >>> Q.extendleft[[5, 6]] >>> Q deque[[6, 5, 2, 1, 3, 4]] >>> Q.pop[] 4 >>> Q.popleft[] 6 >>> Q deque[[5, 2, 1, 3]] >>> Q.rotate[3] >>> Q deque[[2, 1, 3, 5]] >>> Q.rotate[-3] >>> Q deque[[5, 2, 1, 3]] >>> last_three = collections.deque[maxlen=3] >>> for i in range[4]: ... last_three.append[i] ... print ', '.join[str[x] for x in last_three] ... 0 0, 1 0, 1, 2 1, 2, 3 2, 3, 49
>>> from collections import Counter
>>> t = [1,1,1,1,1,2,2,2,3,3,4,5,6,7,8,9]
>>> c = Counter[t]
>>> c
Counter[{1: 5, 2: 3, 3: 2, 4: 1, 5: 1, 6: 1, 7: 1, 8: 1, 9: 1}]
0 >>> from collections import Counter
>>> t = [1,1,1,1,1,2,2,2,3,3,4,5,6,7,8,9]
>>> c = Counter[t]
>>> c
Counter[{1: 5, 2: 3, 3: 2, 4: 1, 5: 1, 6: 1, 7: 1, 8: 1, 9: 1}]
1 >>> from collections import Counter
>>> t = [1,1,1,1,1,2,2,2,3,3,4,5,6,7,8,9]
>>> c = Counter[t]
>>> c
Counter[{1: 5, 2: 3, 3: 2, 4: 1, 5: 1, 6: 1, 7: 1, 8: 1, 9: 1}]
2>>> from collections import Counter
>>> t = [1,1,1,1,1,2,2,2,3,3,4,5,6,7,8,9]
>>> c = Counter[t]
>>> c
Counter[{1: 5, 2: 3, 3: 2, 4: 1, 5: 1, 6: 1, 7: 1, 8: 1, 9: 1}]
3 >>> from collections import Counter
>>> t = [1,1,1,1,1,2,2,2,3,3,4,5,6,7,8,9]
>>> c = Counter[t]
>>> c
Counter[{1: 5, 2: 3, 3: 2, 4: 1, 5: 1, 6: 1, 7: 1, 8: 1, 9: 1}]
4>>> from collections import Counter
>>> t = [1,1,1,1,1,2,2,2,3,3,4,5,6,7,8,9]
>>> c = Counter[t]
>>> c
Counter[{1: 5, 2: 3, 3: 2, 4: 1, 5: 1, 6: 1, 7: 1, 8: 1, 9: 1}]
5>>> from collections import Counter
>>> t = [1,1,1,1,1,2,2,2,3,3,4,5,6,7,8,9]
>>> c = Counter[t]
>>> c
Counter[{1: 5, 2: 3, 3: 2, 4: 1, 5: 1, 6: 1, 7: 1, 8: 1, 9: 1}]
6=
>>> from collections import Counter
>>> t = [1,1,1,1,1,2,2,2,3,3,4,5,6,7,8,9]
>>> c = Counter[t]
>>> c
Counter[{1: 5, 2: 3, 3: 2, 4: 1, 5: 1, 6: 1, 7: 1, 8: 1, 9: 1}]
0[
The original tuple is : [1, 3, 5, 2, 3, 5, 1, 1, 3] The tuple after removing duplicates : [1, 3, 5, 2]0
>>> from collections import Counter
>>> t = [1,1,1,1,1,2,2,2,3,3,4,5,6,7,8,9]
>>> c = Counter[t]
>>> c
Counter[{1: 5, 2: 3, 3: 2, 4: 1, 5: 1, 6: 1, 7: 1, 8: 1, 9: 1}]
5>>> import collections >>> Q = collections.deque[] >>> Q.append[1] >>> Q.appendleft[2] >>> Q.extend[[3, 4]] >>> Q.extendleft[[5, 6]] >>> Q deque[[6, 5, 2, 1, 3, 4]] >>> Q.pop[] 4 >>> Q.popleft[] 6 >>> Q deque[[5, 2, 1, 3]] >>> Q.rotate[3] >>> Q deque[[2, 1, 3, 5]] >>> Q.rotate[-3] >>> Q deque[[5, 2, 1, 3]] >>> last_three = collections.deque[maxlen=3] >>> for i in range[4]: ... last_three.append[i] ... print ', '.join[str[x] for x in last_three] ... 0 0, 1 0, 1, 2 1, 2, 3 2, 3, 48
The original tuple is : [1, 3, 5, 2, 3, 5, 1, 1, 3] The tuple after removing duplicates : [1, 3, 5, 2]3
>>> from collections import Counter
>>> t = [1,1,1,1,1,2,2,2,3,3,4,5,6,7,8,9]
>>> c = Counter[t]
>>> c
Counter[{1: 5, 2: 3, 3: 2, 4: 1, 5: 1, 6: 1, 7: 1, 8: 1, 9: 1}]
0 The original tuple is : [1, 3, 5, 2, 3, 5, 1, 1, 3] The tuple after removing duplicates : [1, 3, 5, 2]5
>>> from collections import Counter
>>> t = [1,1,1,1,1,2,2,2,3,3,4,5,6,7,8,9]
>>> c = Counter[t]
>>> c
Counter[{1: 5, 2: 3, 3: 2, 4: 1, 5: 1, 6: 1, 7: 1, 8: 1, 9: 1}]
3 >>> from collections import Counter
>>> t = [1,1,1,1,1,2,2,2,3,3,4,5,6,7,8,9]
>>> c = Counter[t]
>>> c
Counter[{1: 5, 2: 3, 3: 2, 4: 1, 5: 1, 6: 1, 7: 1, 8: 1, 9: 1}]
4The original tuple is : [1, 3, 5, 2, 3, 5, 1, 1, 3] The tuple after removing duplicates : [1, 3, 5, 2]8
Đầu ra
Viết một chương trình Python để tìm các mục lặp đi lặp lại của một tuple ..
Giải pháp mẫu:-.
Python3
Mã Python: #Create a tuple tuplex = 2, 4, 5, 6, 2, 3, 4, 4, 7 in [tuplex] #return số lần nó xuất hiện trong tuple. ....
Các
>>> import collections >>> Q = collections.deque[] >>> Q.append[1] >>> Q.appendleft[2] >>> Q.extend[[3, 4]] >>> Q.extendleft[[5, 6]] >>> Q deque[[6, 5, 2, 1, 3, 4]] >>> Q.pop[] 4 >>> Q.popleft[] 6 >>> Q deque[[5, 2, 1, 3]] >>> Q.rotate[3] >>> Q deque[[2, 1, 3, 5]] >>> Q.rotate[-3] >>> Q deque[[5, 2, 1, 3]] >>> last_three = collections.deque[maxlen=3] >>> for i in range[4]: ... last_three.append[i] ... print ', '.join[str[x] for x in last_three] ... 0 0, 1 0, 1, 2 1, 2, 3 2, 3, 48
>>> import collections >>> Q = collections.deque[] >>> Q.append[1] >>> Q.appendleft[2] >>> Q.extend[[3, 4]] >>> Q.extendleft[[5, 6]] >>> Q deque[[6, 5, 2, 1, 3, 4]] >>> Q.pop[] 4 >>> Q.popleft[] 6 >>> Q deque[[5, 2, 1, 3]] >>> Q.rotate[3] >>> Q deque[[2, 1, 3, 5]] >>> Q.rotate[-3] >>> Q deque[[5, 2, 1, 3]] >>> last_three = collections.deque[maxlen=3] >>> for i in range[4]: ... last_three.append[i] ... print ', '.join[str[x] for x in last_three] ... 0 0, 1 0, 1, 2 1, 2, 3 2, 3, 49
>>> from collections import Counter
>>> t = [1,1,1,1,1,2,2,2,3,3,4,5,6,7,8,9]
>>> c = Counter[t]
>>> c
Counter[{1: 5, 2: 3, 3: 2, 4: 1, 5: 1, 6: 1, 7: 1, 8: 1, 9: 1}]
0 >>> from collections import Counter
>>> t = [1,1,1,1,1,2,2,2,3,3,4,5,6,7,8,9]
>>> c = Counter[t]
>>> c
Counter[{1: 5, 2: 3, 3: 2, 4: 1, 5: 1, 6: 1, 7: 1, 8: 1, 9: 1}]
1 >>> from collections import Counter
>>> t = [1,1,1,1,1,2,2,2,3,3,4,5,6,7,8,9]
>>> c = Counter[t]
>>> c
Counter[{1: 5, 2: 3, 3: 2, 4: 1, 5: 1, 6: 1, 7: 1, 8: 1, 9: 1}]
2>>> from collections import Counter
>>> t = [1,1,1,1,1,2,2,2,3,3,4,5,6,7,8,9]
>>> c = Counter[t]
>>> c
Counter[{1: 5, 2: 3, 3: 2, 4: 1, 5: 1, 6: 1, 7: 1, 8: 1, 9: 1}]
3 >>> from collections import Counter
>>> t = [1,1,1,1,1,2,2,2,3,3,4,5,6,7,8,9]
>>> c = Counter[t]
>>> c
Counter[{1: 5, 2: 3, 3: 2, 4: 1, 5: 1, 6: 1, 7: 1, 8: 1, 9: 1}]
4>>> from collections import Counter
>>> t = [1,1,1,1,1,2,2,2,3,3,4,5,6,7,8,9]
>>> c = Counter[t]
>>> c
Counter[{1: 5, 2: 3, 3: 2, 4: 1, 5: 1, 6: 1, 7: 1, 8: 1, 9: 1}]
5>>> from collections import Counter
>>> t = [1,1,1,1,1,2,2,2,3,3,4,5,6,7,8,9]
>>> c = Counter[t]
>>> c
Counter[{1: 5, 2: 3, 3: 2, 4: 1, 5: 1, 6: 1, 7: 1, 8: 1, 9: 1}]
6=
>>> from collections import Counter
>>> t = [1,1,1,1,1,2,2,2,3,3,4,5,6,7,8,9]
>>> c = Counter[t]
>>> c
Counter[{1: 5, 2: 3, 3: 2, 4: 1, 5: 1, 6: 1, 7: 1, 8: 1, 9: 1}]
0[
The original tuple is : [1, 3, 5, 2, 3, 5, 1, 1, 3] The tuple after removing duplicates : [1, 3, 5, 2]0
>>> from collections import Counter
>>> t = [1,1,1,1,1,2,2,2,3,3,4,5,6,7,8,9]
>>> c = Counter[t]
>>> c
Counter[{1: 5, 2: 3, 3: 2, 4: 1, 5: 1, 6: 1, 7: 1, 8: 1, 9: 1}]
5>>> import collections >>> Q = collections.deque[] >>> Q.append[1] >>> Q.appendleft[2] >>> Q.extend[[3, 4]] >>> Q.extendleft[[5, 6]] >>> Q deque[[6, 5, 2, 1, 3, 4]] >>> Q.pop[] 4 >>> Q.popleft[] 6 >>> Q deque[[5, 2, 1, 3]] >>> Q.rotate[3] >>> Q deque[[2, 1, 3, 5]] >>> Q.rotate[-3] >>> Q deque[[5, 2, 1, 3]] >>> last_three = collections.deque[maxlen=3] >>> for i in range[4]: ... last_three.append[i] ... print ', '.join[str[x] for x in last_three] ... 0 0, 1 0, 1, 2 1, 2, 3 2, 3, 48
The original tuple is : [1, 3, 5, 2, 3, 5, 1, 1, 3] The tuple after removing duplicates : [1, 3, 5, 2]3
>>> from collections import Counter
>>> t = [1,1,1,1,1,2,2,2,3,3,4,5,6,7,8,9]
>>> c = Counter[t]
>>> c
Counter[{1: 5, 2: 3, 3: 2, 4: 1, 5: 1, 6: 1, 7: 1, 8: 1, 9: 1}]
0 The original tuple is : [1, 3, 5, 2, 3, 5, 1, 1, 3] The tuple after removing duplicates : [1, 3, 5, 2]5
>>> from collections import Counter
>>> t = [1,1,1,1,1,2,2,2,3,3,4,5,6,7,8,9]
>>> c = Counter[t]
>>> c
Counter[{1: 5, 2: 3, 3: 2, 4: 1, 5: 1, 6: 1, 7: 1, 8: 1, 9: 1}]
3 >>> from collections import Counter
>>> t = [1,1,1,1,1,2,2,2,3,3,4,5,6,7,8,9]
>>> c = Counter[t]
>>> c
Counter[{1: 5, 2: 3, 3: 2, 4: 1, 5: 1, 6: 1, 7: 1, 8: 1, 9: 1}]
4The original tuple is : [1, 3, 5, 2, 3, 5, 1, 1, 3] The tuple after removing duplicates : [1, 3, 5, 2]8
Đầu ra
The original tuple is : [1, 3, 5, 2, 3, 5, 1, 1, 3] The tuple after removing duplicates : [1, 3, 5, 2]
Làm thế nào để tôi tìm thấy một mục lặp đi lặp lại trong Tuple Python?
Python3
Các
>>> import collections >>> Q = collections.deque[] >>> Q.append[1] >>> Q.appendleft[2] >>> Q.extend[[3, 4]] >>> Q.extendleft[[5, 6]] >>> Q deque[[6, 5, 2, 1, 3, 4]] >>> Q.pop[] 4 >>> Q.popleft[] 6 >>> Q deque[[5, 2, 1, 3]] >>> Q.rotate[3] >>> Q deque[[2, 1, 3, 5]] >>> Q.rotate[-3] >>> Q deque[[5, 2, 1, 3]] >>> last_three = collections.deque[maxlen=3] >>> for i in range[4]: ... last_three.append[i] ... print ', '.join[str[x] for x in last_three] ... 0 0, 1 0, 1, 2 1, 2, 3 2, 3, 48
[
[2, 4, 5, 6, 2, 3, 4, 4, 7] 316
>>> from collections import Counter
>>> t = [1,1,1,1,1,2,2,2,3,3,4,5,6,7,8,9]
>>> c = Counter[t]
>>> c
Counter[{1: 5, 2: 3, 3: 2, 4: 1, 5: 1, 6: 1, 7: 1, 8: 1, 9: 1}]
3 >>> from collections import Counter
>>> t = [1,1,1,1,1,2,2,2,3,3,4,5,6,7,8,9]
>>> c = Counter[t]
>>> c
Counter[{1: 5, 2: 3, 3: 2, 4: 1, 5: 1, 6: 1, 7: 1, 8: 1, 9: 1}]
4>>> from collections import Counter
>>> t = [1,1,1,1,1,2,2,2,3,3,4,5,6,7,8,9]
>>> c = Counter[t]
>>> c
Counter[{1: 5, 2: 3, 3: 2, 4: 1, 5: 1, 6: 1, 7: 1, 8: 1, 9: 1}]
5[2, 4, 5, 6, 2, 3, 4, 4, 7] 320
=
[2, 4, 5, 6, 2, 3, 4, 4, 7] 322
[2, 4, 5, 6, 2, 3, 4, 4, 7] 323
[2, 4, 5, 6, 2, 3, 4, 4, 7] 324
[2, 4, 5, 6, 2, 3, 4, 4, 7] 325
[2, 4, 5, 6, 2, 3, 4, 4, 7] 326
[2, 4, 5, 6, 2, 3, 4, 4, 7] 327
[2, 4, 5, 6, 2, 3, 4, 4, 7] 328
[2, 4, 5, 6, 2, 3, 4, 4, 7] 324
[2, 4, 5, 6, 2, 3, 4, 4, 7] 330
[2, 4, 5, 6, 2, 3, 4, 4, 7] 325
[2, 4, 5, 6, 2, 3, 4, 4, 7] 332
[2, 4, 5, 6, 2, 3, 4, 4, 7] 333
[2, 4, 5, 6, 2, 3, 4, 4, 7] 334
[2, 4, 5, 6, 2, 3, 4, 4, 7] 335
=
>>> from collections import Counter
>>> t = [1,1,1,1,1,2,2,2,3,3,4,5,6,7,8,9]
>>> c = Counter[t]
>>> c
Counter[{1: 5, 2: 3, 3: 2, 4: 1, 5: 1, 6: 1, 7: 1, 8: 1, 9: 1}]
0[2, 4, 5, 6, 2, 3, 4, 4, 7] 338
>>> import collections >>> Q = collections.deque[] >>> Q.append[1] >>> Q.appendleft[2] >>> Q.extend[[3, 4]] >>> Q.extendleft[[5, 6]] >>> Q deque[[6, 5, 2, 1, 3, 4]] >>> Q.pop[] 4 >>> Q.popleft[] 6 >>> Q deque[[5, 2, 1, 3]] >>> Q.rotate[3] >>> Q deque[[2, 1, 3, 5]] >>> Q.rotate[-3] >>> Q deque[[5, 2, 1, 3]] >>> last_three = collections.deque[maxlen=3] >>> for i in range[4]: ... last_three.append[i] ... print ', '.join[str[x] for x in last_three] ... 0 0, 1 0, 1, 2 1, 2, 3 2, 3, 48
[
[2, 4, 5, 6, 2, 3, 4, 4, 7] 341
>>> from collections import Counter
>>> t = [1,1,1,1,1,2,2,2,3,3,4,5,6,7,8,9]
>>> c = Counter[t]
>>> c
Counter[{1: 5, 2: 3, 3: 2, 4: 1, 5: 1, 6: 1, 7: 1, 8: 1, 9: 1}]
3 >>> from collections import Counter
>>> t = [1,1,1,1,1,2,2,2,3,3,4,5,6,7,8,9]
>>> c = Counter[t]
>>> c
Counter[{1: 5, 2: 3, 3: 2, 4: 1, 5: 1, 6: 1, 7: 1, 8: 1, 9: 1}]
4The original tuple is : [1, 3, 5, 2, 3, 5, 1, 1, 3] The tuple after removing duplicates : [1, 3, 5, 2]8
Đầu ra
The original tuple is : [1, 3, 5, 2, 3, 5, 1, 1, 3] The tuple after removing duplicates : [1, 3, 5, 2]