The question, is the provided example just an "example" or exact what you looking for? There are many mixed answers here, and I dont understand the complexibility of the accepted one.
To find out if ANY content of the array of needles exists in the string, and quickly return true or false:
$string = 'abcdefg';
if[str_replace[array['a', 'c', 'd'], '', $string] != $string]{
echo 'at least one of the needles where found';
};
If, so, please give @Leon credit for that.
To find out if ALL values of the array of needles exists in the string, as in this case, all three 'a', 'b'
and 'c'
MUST be present, like you mention as your "for example"
echo 'All the letters are found in the string!';
Many answers here is out of that context, but I doubt that the intension of the question as you marked as resolved. E.g. The accepted answer is a needle of
$array = array['burger', 'melon', 'cheese', 'milk'];
What if all those words MUST be found in the string?
Then you try out some "not accepted answers"
on this page.
[PHP 4, PHP 5, PHP 7, PHP 8] strpos — Find the position of the first occurrence of a substring in a string strpos[string The string to
search in. Prior to PHP 8.0.0, if If specified, search will start this number of characters counted from the beginning
of the string. If the offset is negative, the search will start this number of characters counted from the end of the string. Description
$haystack
, string $needle
, int $offset
= 0]: int|falseParameters
haystack
needle
needle
is not a string, it is converted to an integer and applied as the ordinal value of a character. This behavior is deprecated as of PHP 7.3.0, and relying on it is highly discouraged. Depending on the intended behavior, the needle
should either be explicitly cast to string, or an explicit call to chr[] should be performed. offset
Return Values
Returns the position of where the needle exists relative to the beginning of the haystack
string [independent of offset]. Also note that string positions start at 0, and not 1.
Returns false
if the needle was not found.
Warning
This function may return Boolean
false
, but may also return a non-Boolean value which evaluates to false
. Please read the section on Booleans for more information. Use the === operator for testing the return value of this function.
Changelog
8.0.0 | Passing an int as needle is no longer supported.
|
7.3.0 | Passing an int as needle has been deprecated.
|
7.1.0 | Support for negative offset s has been added.
|
Examples
Example #1 Using ===
Notes
Note: This function is binary-safe.
See Also
- stripos[] - Find the position of the first occurrence of a case-insensitive substring in a string
- str_contains[] - Determine if a string contains a given substring
- str_ends_with[] - Checks if a string ends with a given substring
- str_starts_with[] - Checks if a string starts with a given substring
- strrpos[] - Find the position of the last occurrence of a substring in a string
- strripos[] - Find the position of the last occurrence of a case-insensitive substring in a string
- strstr[] - Find the first occurrence of a string
- strpbrk[] - Search a string for any of a set of characters
- substr[] - Return part of a string
- preg_match[] - Perform a regular expression match
Suggested re-write for pink WARNING box ¶
14 years ago
WARNING
As strpos may return either FALSE [substring absent] or 0 [substring at start of string], strict versus loose equivalency operators must be used very carefully.
To know that a substring is absent, you must use:
=== FALSE
To know that a substring is present [in any position including 0], you can use either of:
!== FALSE [recommended]
> -1 [note: or greater than any negative number]
To know that a substring is at the start of the string, you must use:
=== 0
To know that a substring is in any position other than the start, you can use any of:
> 0 [recommended]
!= 0 [note: but not !== 0 which also equates to FALSE]
!= FALSE [disrecommended as highly confusing]
Also note that you cannot compare a value of "" to the returned value of strpos. With a loose equivalence operator [== or !=] it will return results which don't distinguish between the substring's presence versus position. With a strict equivalence operator [=== or !==] it will always return false.
martijn at martijnfrazer dot nl ¶
10 years ago
This is a function I wrote to find all occurrences of a string, using strpos recursively.
This is how you use it:
fabio at naoimporta dot com ¶
6 years ago
It is interesting to be aware of the behavior when the treatment of strings with characters using different encodings.
qrworld.net ¶
7 years ago
I found a function in this post //softontherocks.blogspot.com/2014/11/buscar-multiples-textos-en-un-texto-con.html
that implements the search in both ways, case sensitive or case insensitive, depending on an input parameter.
The function is:
function getMultiPos[$haystack, $needles, $sensitive=true, $offset=0]{
foreach[$needles as $needle] {
$result[$needle] = [$sensitive] ? strpos[$haystack, $needle, $offset] : stripos[$haystack, $needle, $offset];
}
return $result;
}
It was very useful for me.
Lurvik ¶
8 years ago
Don't know if already posted this, but if I did this is an improvement.
This function will check if a string contains a needle. It _will_ work with arrays and multidimensional arrays [I've tried with a > 16 dimensional array and had no problem].
gambajaja at yahoo dot com ¶
12 years ago
Simple fixes:
hu60 dot cn at gmail dot com ¶
3 years ago
A more accurate imitation of the PHP function session_start[].
Function my_session_start[] does something similar to session_start[] that has the default configure, and the session files generated by the two are binary compatible.
The code may help people increase their understanding of the principles of the PHP session.