Python convert backslash to forward slash

I am working in python and I need to convert this:

C:\folderA\folderB to C:/folderA/folderB

I have three approaches:

dir = s.replace['\\','/']

dir = os.path.normpath[s] 

dir = os.path.normcase[s]

In each scenario the output has been

C:folderAfolderB

I'm not sure what I am doing wrong, any suggestions?

martineau

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asked Aug 5, 2014 at 19:39

3

I recently found this and thought worth sharing:

import os

path = "C:\\temp\myFolder\example\\"
newPath = path.replace[os.sep, '/']
print[newPath]  # -> C:/temp/myFolder/example/

martineau

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answered May 7, 2018 at 19:27

NumabyteNumabyte

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Your specific problem is the order and escaping of your replace arguments, should be

s.replace['\\', '/']

Then there's:

posixpath.join[*s.split['\\']]

Which on a *nix platform is equivalent to:

os.path.join[*s.split['\\']]

But don't rely on that on Windows because it will prefer the platform-specific separator. Also:

Note that on Windows, since there is a current directory for each drive, os.path.join["c:", "foo"] represents a path relative to the current directory on drive C: [c:foo], not c:\foo.

answered Aug 5, 2014 at 19:47

Jason SJason S

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3

Try

path = '/'.join[path.split['\\']]

answered Aug 5, 2014 at 19:41

TheoretiCALTheoretiCAL

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Path names are formatted differently in Windows. the solution is simple, suppose you have a path string like this:

data_file = "/Users/username/Downloads/PMLSdata/series.csv"

simply you have to change it to this: [adding r front of the path]

data_file = r"/Users/username/Downloads/PMLSdata/series.csv"

The modifier r before the string tells Python that this is a raw string. In raw strings, the backslash is interpreted literally, not as an escape character.

answered Jun 28, 2018 at 7:39

scapascapa

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Sorry for being late to the party, but I wonder no one has suggested the pathlib-library.

pathlib is a module for "Object-oriented filesystem paths"

To convert from windows-style [backslash]-paths to forward-slashes [as typically for Posix-Paths] you can do so in a very verbose [AND platform-independant] fashion with pathlib:

import pathlib

pathlib.PureWindowsPath[r"C:\folderA\folderB"].as_posix[]
>>> 'C:/folderA/folderB'

Be aware that the example uses the string-literal "r" [to avoid having "\" as escape-char] In other cases the path should be quoted properly [with double backslashes] "C:\\folderA\\folderB"

answered May 14, 2021 at 14:55

StefanStefan

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To define the path's variable you have to add r initially, then add the replace statement .replace['\\', '/'] at the end.

for example:

In>>  path2 = r'C:\Users\User\Documents\Project\Em2Lph\'.replace['\\', '/']
In>>  path2 
Out>> 'C:/Users/User/Documents/Project/Em2Lph/'

This solution requires no additional libraries

answered Mar 21, 2018 at 10:53

Mohammad ElNesrMohammad ElNesr

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1

How about :

import ntpath
import posixpath
.
.
.
dir = posixpath.join[*ntpath.split[s]]
.
.

answered Sep 28, 2017 at 6:29

1

This can work also:

def slash_changer[directory]:

if "\\" in directory:
    return directory.replace[os.sep, '/']
else:
    return directory

print[slash_changer[os.getcwd[]]]

answered Nov 19, 2021 at 22:04

this is the perfect solution put the letter 'r' before the string that you want to convert to avoid all special characters likes '\t' and '\f'... like the example below:

str= r"\test\hhd"

print["windows path:",str.replace["\\","\\\\"]]
print["Linux path:",str.replace["\\","/"]]

result:

windows path: \\test\\hhd
Linux path: /test/hhd

answered Mar 26 at 11:02

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