How do i add one object to another in javascript?

Given

options = {
 underscored: true
}

products = {
 foo: bar
}

I'd like to get

products = {
 underscored: true
 foo: bar
}

Is it possible to push an object into another object in Javascript?

asked Mar 23, 2012 at 17:35

1

ES5


function mix[source, target] {
   for[var key in source] {
     if [source.hasOwnProperty[key]] {
        target[key] = source[key];
     }
   }

}

  mix[options, products];

ES6 - this will mutate objectToMergeTo

const combinedObject = Object.assign[objectToMergeTo, source1, source2]

ES7 [syntax beauty with spread operator] - this version however creates a new instance, you can't add into an object with spread operator.

const combined = { ...source1, ...source2 }

answered Mar 23, 2012 at 17:39

4

You could do this:

for[var key in options] {
    products[key] = options[key];
}

That would effectively combine the two objects' variables.

answered Mar 23, 2012 at 17:38

1

var options = {
    underscored: true
};
var products = {
    foo: 'bar'
};
products.underscored = options.underscored;
alert[products.underscored+":"+products.foo];

put quotes around the 'bar' to make it actually have a value, semi-colons and var on the objects, but you get the point.

EDIT: also worth noting;

products.options = options;
alert[products.options.underscored];//alerts true

answered Mar 23, 2012 at 17:40

Mark SchultheissMark Schultheiss

30.8k11 gold badges67 silver badges95 bronze badges

you can use jquery.extend[products,options]. jQuery.extend combines two objects, over rides the matching element values in the target object and returns resulting object. For more info ://api.jquery.com/jquery.extend/

answered Apr 15, 2014 at 7:40

The Object.assign[] method copies all enumerable own properties from one or more source objects to a target object. It returns the modified target object.

Try it

Syntax

Object.assign[target, ...sources]

Parameters

target

The target object — what to apply the sources' properties to, which is returned after it is modified.

sources

The source object[s] — objects containing the properties you want to apply.

Return value

The target object.

Description

Properties in the target object are overwritten by properties in the sources if they have the same key. Later sources' properties overwrite earlier ones.

The Object.assign[] method only copies enumerable and own properties from a source object to a target object. It uses [[Get]] on the source and [[Set]] on the target, so it will invoke getters and setters. Therefore it assigns properties, versus copying or defining new properties. This may make it unsuitable for merging new properties into a prototype if the merge sources contain getters.

For copying property definitions [including their enumerability] into prototypes, use Object.getOwnPropertyDescriptor[] and Object.defineProperty[] instead.

Both String and Symbol properties are copied.

In case of an error, for example if a property is non-writable, a TypeError is raised, and the target object is changed if any properties are added before the error is raised.

Note: Object.assign[] does not throw on null or undefined sources.

Examples

Cloning an object

const obj = { a: 1 };
const copy = Object.assign[{}, obj];
console.log[copy]; // { a: 1 }

Warning for Deep Clone

For deep cloning, we need to use alternatives, because Object.assign[] copies property values.

If the source value is a reference to an object, it only copies the reference value.

const obj1 = { a: 0, b: { c: 0 } };
const obj2 = Object.assign[{}, obj1];
console.log[obj2]; // { a: 0, b: { c: 0 } }

obj1.a = 1;
console.log[obj1]; // { a: 1, b: { c: 0 } }
console.log[obj2]; // { a: 0, b: { c: 0 } }

obj2.a = 2;
console.log[obj1]; // { a: 1, b: { c: 0 } }
console.log[obj2]; // { a: 2, b: { c: 0 } }

obj2.b.c = 3;
console.log[obj1]; // { a: 1, b: { c: 3 } }
console.log[obj2]; // { a: 2, b: { c: 3 } }

// Deep Clone
const obj3 = { a: 0, b: { c: 0 } };
const obj4 = JSON.parse[JSON.stringify[obj3]];
obj3.a = 4;
obj3.b.c = 4;
console.log[obj4]; // { a: 0, b: { c: 0 } }

Merging objects

const o1 = { a: 1 };
const o2 = { b: 2 };
const o3 = { c: 3 };

const obj = Object.assign[o1, o2, o3];
console.log[obj]; // { a: 1, b: 2, c: 3 }
console.log[o1];  // { a: 1, b: 2, c: 3 }, target object itself is changed.

Merging objects with same properties

const o1 = { a: 1, b: 1, c: 1 };
const o2 = { b: 2, c: 2 };
const o3 = { c: 3 };

const obj = Object.assign[{}, o1, o2, o3];
console.log[obj]; // { a: 1, b: 2, c: 3 }

The properties are overwritten by other objects that have the same properties later in the parameters order.

Copying symbol-typed properties

const o1 = { a: 1 };
const o2 = { [Symbol['foo']]: 2 };

const obj = Object.assign[{}, o1, o2];
console.log[obj]; // { a : 1, [Symbol["foo"]]: 2 } [cf. bug 1207182 on Firefox]
Object.getOwnPropertySymbols[obj]; // [Symbol[foo]]

Properties on the prototype chain and non-enumerable properties cannot be copied

const obj = Object.create[{ foo: 1 }, { // foo is on obj's prototype chain.
  bar: {
    value: 2  // bar is a non-enumerable property.
  },
  baz: {
    value: 3,
    enumerable: true  // baz is an own enumerable property.
  }
}];

const copy = Object.assign[{}, obj];
console.log[copy]; // { baz: 3 }

Primitives will be wrapped to objects

const v1 = 'abc';
const v2 = true;
const v3 = 10;
const v4 = Symbol['foo'];

const obj = Object.assign[{}, v1, null, v2, undefined, v3, v4];
// Primitives will be wrapped, null and undefined will be ignored.
// Note, only string wrappers can have own enumerable properties.
console.log[obj]; // { "0": "a", "1": "b", "2": "c" }

Exceptions will interrupt the ongoing copying task

const target = Object.defineProperty[{}, 'foo', {
  value: 1,
  writable: false
}]; // target.foo is a read-only property

Object.assign[target, { bar: 2 }, { foo2: 3, foo: 3, foo3: 3 }, { baz: 4 }];
// TypeError: "foo" is read-only
// The Exception is thrown when assigning target.foo

console.log[target.bar];  // 2, the first source was copied successfully.
console.log[target.foo2]; // 3, the first property of the second source was copied successfully.
console.log[target.foo];  // 1, exception is thrown here.
console.log[target.foo3]; // undefined, assign method has finished, foo3 will not be copied.
console.log[target.baz];  // undefined, the third source will not be copied either.

Copying accessors

const obj = {
  foo: 1,
  get bar[] {
    return 2;
  }
};

let copy = Object.assign[{}, obj];
console.log[copy];
// { foo: 1, bar: 2 }
// The value of copy.bar is obj.bar's getter's return value.

// This is an assign function that copies full descriptors
function completeAssign[target, ...sources] {
  sources.forEach[[source] => {
    const descriptors = Object.keys[source].reduce[[descriptors, key] => {
      descriptors[key] = Object.getOwnPropertyDescriptor[source, key];
      return descriptors;
    }, {}];

    // By default, Object.assign copies enumerable Symbols, too
    Object.getOwnPropertySymbols[source].forEach[[sym] => {
      const descriptor = Object.getOwnPropertyDescriptor[source, sym];
      if [descriptor.enumerable] {
        descriptors[sym] = descriptor;
      }
    }];
    Object.defineProperties[target, descriptors];
  }];
  return target;
}

copy = completeAssign[{}, obj];
console.log[copy];
// { foo:1, get bar[] { return 2 } }

Specifications

Specification
ECMAScript Language Specification
# sec-object.assign

Browser compatibility

BCD tables only load in the browser

See also

How do you combine two objects?

To merge objects into a new one that has all properties of the merged objects, you have two options: Use a spread operator [ ... ] Use the Object. assign[] method.

Can you nest objects in JavaScript?

You can create nested objects within a nested object. In the following example, Salary is an object that resides inside the main object named Employee . The dot notation can access the property of nested objects.

How do you add a new item to an object at a specific position?

Use the insert[] function[inserts the provided value at the specified position] to insert the given item at the first position[index=0] into the list by passing the index value as 0 and the item to be inserted as arguments to it.

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