Nhiệm vụ là tìm số lượng số lẻ trong một số nguyên.
count_odd_digits[n]:
Với một số nguyên không âm, hãy tính bao nhiêu chữ số của nó là số lẻ.
example:
count_odd_digits[123450] → 3 #digits 1,3, and 5 are odd
Tôi có cho đến nay:
def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
Nhưng tôi vẫn đang thất bại trong các bài kiểm tra của mình, có gì sai trong mã của tôi?
Zondo
19.3k7 Huy hiệu vàng43 Huy hiệu bạc83 Huy hiệu Đồng7 gold badges43 silver badges83 bronze badges
Đã hỏi ngày 6 tháng 3 năm 2016 lúc 1:08Mar 6, 2016 at 1:08
3
Bạn có một số vấn đề:
4 là hoàn toàn vô dụng. Bạn không bao giờ muốn trả lạicount_odd_digits[123450] → 3 #digits 1,3, and 5 are odd
5; Bạn chỉ muốn tiếp tục. Vì tất cả những gì bạn đang làm là tiếp tục, nó có thể được loại bỏ.count_odd_digits[123450] → 3 #digits 1,3, and 5 are odd
6 đang thử nghiệm sai. Bạn muốn kiểm tracount_odd_digits[123450] → 3 #digits 1,3, and 5 are odd
7, không phảicount_odd_digits[123450] → 3 #digits 1,3, and 5 are odd
8.count_odd_digits[123450] → 3 #digits 1,3, and 5 are odd
Thay đổi mã thành điều này:
def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
Sẽ dễ dàng hơn khi sử dụng biểu thức máy phát:
def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
Đã trả lời ngày 6 tháng 3 năm 2016 lúc 1:14Mar 6, 2016 at 1:14
Zondozondozondo
19.3k7 Huy hiệu vàng43 Huy hiệu bạc83 Huy hiệu Đồng7 gold badges43 silver badges83 bronze badges
9
Đã hỏi ngày 6 tháng 3 năm 2016 lúc 1:08
Bạn có một số vấn đề:
def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] %2 == 1:
ans += 1
# drop the elif part
# return after the for loop
return ans
count_odd_digits[123450]
count_odd_digits[123450] → 3 #digits 1,3, and 5 are odd
4 là hoàn toàn vô dụng. Bạn không bao giờ muốn trả lại count_odd_digits[123450] → 3 #digits 1,3, and 5 are odd
5; Bạn chỉ muốn tiếp tục. Vì tất cả những gì bạn đang làm là tiếp tục, nó có thể được loại bỏ.Mar 6, 2016 at 1:12
count_odd_digits[123450] → 3 #digits 1,3, and 5 are odd
6 đang thử nghiệm sai. Bạn muốn kiểm tra count_odd_digits[123450] → 3 #digits 1,3, and 5 are odd
7, không phải count_odd_digits[123450] → 3 #digits 1,3, and 5 are odd
8.MSeifertThay đổi mã thành điều này:33 gold badges321 silver badges338 bronze badges
Sẽ dễ dàng hơn khi sử dụng biểu thức máy phát:
def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] %2 == 1:
ans += 1
return ans
Đã trả lời ngày 6 tháng 3 năm 2016 lúc 1:14Mar 6, 2016 at 1:10
Zondozondokartikmaji
Phần
9 sẽ ngay lập tức chấm dứt chức năng của bạn. Ngoài ra, bạn nên chuyển đổi count_odd_digits[123450] → 3 #digits 1,3, and 5 are odd
0 thành def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
1 không phải là chuỗi hoàn chỉnh.7 silver badges21 bronze badgesdef count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
1
Một chức năng làm việc có thể trông như thế này:
def count_odd_digits[n]:
ans = 0
while n:
digit = n % 10
if digit % 2:
ans += 1
n //= 10
return ans
Đã trả lời ngày 6 tháng 3 năm 2016 lúc 1:12Mar 6, 2016 at 1:27
MSEifertMseifertAkavall
139K33 Huy hiệu vàng321 Huy hiệu bạc338 Huy hiệu đồng49 gold badges202 silver badges246 bronze badges
0
Các mã cần thiết được cung cấp dưới đây. num = int [input [nhập bất kỳ số nào để kiểm tra xem nó là lẻ hay thậm chí: Đầu ra] đầu ra: Nhập bất kỳ số nào để kiểm tra xem nó là lẻ hay thậm chí: 887 887 là lẻ.
Input : test_list = [345, 893, 1948, 34, 2346] Output : Odd digit sum : 36 Even digit sum : 40 Explanation : 3 + 5 + 9 + 3 + 1 + 9 + 3 + 3 = 36, odd summation.
Input : test_list = [345, 893] Output : Odd digit sum : 20 Even digit sum : 12 Explanation : 4 + 8 = 12, even summation.
Làm thế nào để bạn lọc các số lẻ trong python?Using loop, str[] and int[]
Để lọc các số lẻ từ danh sách trong Python, hãy sử dụng hàm tích hợp Filter []. Vượt qua hàm trả về đúng cho một số lẻ và danh sách các số, làm đối số cho hàm lọc [].
Python3
def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
2def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
3 def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
4def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
5def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
6def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
7def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
6def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
9def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
6def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
1def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
6def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
3def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
4def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
1def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
3 def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
3def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
1def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
3 def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
3def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
4def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
3 def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
3def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
1def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
8def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
3 count_odd_digits[123450] → 3 #digits 1,3, and 5 are odd
27count_odd_digits[123450] → 3 #digits 1,3, and 5 are odd
28def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] %2 == 1:
ans += 1
# drop the elif part
# return after the for loop
return ans
count_odd_digits[123450]
9def count_odd_digits[n]:
ans = 0
while n:
digit = n % 10
if digit % 2:
ans += 1
n //= 10
return ans
2def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
05def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
7 def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
8def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
9 def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
2___def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
4def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
8def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
3 count_odd_digits[123450] → 3 #digits 1,3, and 5 are odd
27count_odd_digits[123450] → 3 #digits 1,3, and 5 are odd
28def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] %2 == 1:
ans += 1
# drop the elif part
# return after the for loop
return ans
count_odd_digits[123450]
9def count_odd_digits[n]:
ans = 0
while n:
digit = n % 10
if digit % 2:
ans += 1
n //= 10
return ans
2def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
31def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
7 def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
8def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
9 def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
2def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
7 def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] %2 == 1:
ans += 1
# drop the elif part
# return after the for loop
return ans
count_odd_digits[123450]
3__def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] %2 == 1:
ans += 1
# drop the elif part
# return after the for loop
return ans
count_odd_digits[123450]
7def count_odd_digits[n]:
ans = 0
while n:
digit = n % 10
if digit % 2:
ans += 1
n //= 10
return ans
4def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] %2 == 1:
ans += 1
return ans
6Phương pháp 4: Sử dụng hàm liệt kê
def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
5def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
6Input : test_list = [345, 893, 1948, 34, 2346] Output : Odd digit sum : 36 Even digit sum : 40 Explanation : 3 + 5 + 9 + 3 + 1 + 9 + 3 + 3 = 36, odd summation.4
def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
8 def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
9Input : test_list = [345, 893, 1948, 34, 2346] Output : Odd digit sum : 36 Even digit sum : 40 Explanation : 3 + 5 + 9 + 3 + 1 + 9 + 3 + 3 = 36, odd summation.7
def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
5def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
6Input : test_list = [345, 893] Output : Odd digit sum : 20 Even digit sum : 12 Explanation : 4 + 8 = 12, even summation.0
def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
8 def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
9Input : test_list = [345, 893] Output : Odd digit sum : 20 Even digit sum : 12 Explanation : 4 + 8 = 12, even summation.3
Đầu ra
count_odd_digits[123450] → 3 #digits 1,3, and 5 are odd
0
1def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
8def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
3 def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
27count_odd_digits[123450] → 3 #digits 1,3, and 5 are odd
28__Using loop and sum[]count_odd_digits[123450] → 3 #digits 1,3, and 5 are odd
def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
05def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
7 def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] %2 == 1:
ans += 1
# drop the elif part
# return after the for loop
return ans
count_odd_digits[123450]
3__Python3
def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
2def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
3 def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
4def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
5def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
6def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
7def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
6def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
9def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
6def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
1def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
6def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
3def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
4def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
5def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
6def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
7 def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
8 def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
9def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
0def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
1def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
3 def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
3def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
4def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
3 def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
3def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
7 def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
8def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
9 def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] %2 == 1:
ans += 1
# drop the elif part
# return after the for loop
return ans
count_odd_digits[123450]
0Các
def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] %2 == 1:
ans += 1
# drop the elif part
# return after the for loop
return ans
count_odd_digits[123450]
1def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
4___def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
5def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
6Input : test_list = [345, 893, 1948, 34, 2346] Output : Odd digit sum : 36 Even digit sum : 40 Explanation : 3 + 5 + 9 + 3 + 1 + 9 + 3 + 3 = 36, odd summation.4
def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
8 def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
9Input : test_list = [345, 893, 1948, 34, 2346] Output : Odd digit sum : 36 Even digit sum : 40 Explanation : 3 + 5 + 9 + 3 + 1 + 9 + 3 + 3 = 36, odd summation.7
def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
5def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
6Input : test_list = [345, 893] Output : Odd digit sum : 20 Even digit sum : 12 Explanation : 4 + 8 = 12, even summation.0
def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
8 def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
9Input : test_list = [345, 893] Output : Odd digit sum : 20 Even digit sum : 12 Explanation : 4 + 8 = 12, even summation.3
Đầu ra
count_odd_digits[123450] → 3 #digits 1,3, and 5 are odd
0Phương pháp 3: Sử dụng danh sách hiểu & nbsp; Using list comprehension
Python3
def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
2def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
3 def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
4def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
5def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
6def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
7def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
6def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
9def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
6def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
1def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
6def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
3def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
4def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
1def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
3 def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
3def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
4def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
3 def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
3def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
7 def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
8def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
9 def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] %2 == 1:
ans += 1
# drop the elif part
# return after the for loop
return ans
count_odd_digits[123450]
0Các
def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] %2 == 1:
ans += 1
# drop the elif part
# return after the for loop
return ans
count_odd_digits[123450]
1def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
4___def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
5def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
6Input : test_list = [345, 893, 1948, 34, 2346] Output : Odd digit sum : 36 Even digit sum : 40 Explanation : 3 + 5 + 9 + 3 + 1 + 9 + 3 + 3 = 36, odd summation.4
def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
8 def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
9Input : test_list = [345, 893, 1948, 34, 2346] Output : Odd digit sum : 36 Even digit sum : 40 Explanation : 3 + 5 + 9 + 3 + 1 + 9 + 3 + 3 = 36, odd summation.7
def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
5def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
6Input : test_list = [345, 893, 1948, 34, 2346] Output : Odd digit sum : 36 Even digit sum : 40 Explanation : 3 + 5 + 9 + 3 + 1 + 9 + 3 + 3 = 36, odd summation.4
def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
8 def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
9Input : test_list = [345, 893, 1948, 34, 2346] Output : Odd digit sum : 36 Even digit sum : 40 Explanation : 3 + 5 + 9 + 3 + 1 + 9 + 3 + 3 = 36, odd summation.7
def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
5def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
6Input : test_list = [345, 893] Output : Odd digit sum : 20 Even digit sum : 12 Explanation : 4 + 8 = 12, even summation.0
def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
8 def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
9Input : test_list = [345, 893] Output : Odd digit sum : 20 Even digit sum : 12 Explanation : 4 + 8 = 12, even summation.3
Đầu ra
count_odd_digits[123450] → 3 #digits 1,3, and 5 are odd
2Phương pháp 3: Sử dụng danh sách hiểu & nbsp; Using the enumerate function
Python3
def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
2def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
3 def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
4def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
5def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
6def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
7def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
6def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
9def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
6def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
1def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
6def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
3def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
4def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
1def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
3 def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
3def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
4def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
3 def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
3def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
1def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
8def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
3 count_odd_digits[123450] → 3 #digits 1,3, and 5 are odd
27count_odd_digits[123450] → 3 #digits 1,3, and 5 are odd
28def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] %2 == 1:
ans += 1
# drop the elif part
# return after the for loop
return ans
count_odd_digits[123450]
9def count_odd_digits[n]:
ans = 0
while n:
digit = n % 10
if digit % 2:
ans += 1
n //= 10
return ans
2def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
05def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
7 def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
8def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
9 def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
2___def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
4def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
8def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
3 count_odd_digits[123450] → 3 #digits 1,3, and 5 are odd
27count_odd_digits[123450] → 3 #digits 1,3, and 5 are odd
28def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] %2 == 1:
ans += 1
# drop the elif part
# return after the for loop
return ans
count_odd_digits[123450]
9def count_odd_digits[n]:
ans = 0
while n:
digit = n % 10
if digit % 2:
ans += 1
n //= 10
return ans
2def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
31def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
7 def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
8def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
9 def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[n] %2 == 1:
ans += 1
elif n[i]==0:
return None
2def count_odd_digits[n]:
return sum[int[i] % 2 for i in str[n]]
7 def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] %2 == 1:
ans += 1
# drop the elif part
# return after the for loop
return ans
count_odd_digits[123450]
3__def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
5def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
6Input : test_list = [345, 893, 1948, 34, 2346] Output : Odd digit sum : 36 Even digit sum : 40 Explanation : 3 + 5 + 9 + 3 + 1 + 9 + 3 + 3 = 36, odd summation.4
def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
8 def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
9Input : test_list = [345, 893, 1948, 34, 2346] Output : Odd digit sum : 36 Even digit sum : 40 Explanation : 3 + 5 + 9 + 3 + 1 + 9 + 3 + 3 = 36, odd summation.7
def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
5def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
6Input : test_list = [345, 893] Output : Odd digit sum : 20 Even digit sum : 12 Explanation : 4 + 8 = 12, even summation.0
def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
8 def count_odd_digits[n]:
ans = 0
for i in str[n]:
if int[i] % 2:
ans += 1
return ans
9Input : test_list = [345, 893] Output : Odd digit sum : 20 Even digit sum : 12 Explanation : 4 + 8 = 12, even summation.3
Đầu ra
count_odd_digits[123450] → 3 #digits 1,3, and 5 are odd
2