How do i make an even odd game in python?
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Given three positive integers X, Y and P. Here P denotes the number of turns. Whenever the turn is odd X is multiplied by 2 and in every even turn Y is multiplied by 2. The task is to find the value of max(X, Y) ÷ min(X, Y) after the complete P turns. Show Examples :
Lets play the above game for 8 turns : | i | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | |------|---|----|----|----|----|----|----|-----|-----| | X(i) | X | 2X | 2X | 4X | 4X | 8X | 8X | 16X | 16X | | Y(i) | Y | Y | 2Y | 2Y | 4Y | 4Y | 8Y | 8Y | 16Y | Here we can easily
spot a pattern : if i is even, then X(i) = z * X and Y(i) = z * Y. if i is odd, then X(i) = 2*z * X and Y(i) = z * Y. Here z is actually the power of 2. So, we can simply say – If P is even output will be max(X, Y) ÷ min(X, Y) else output will be max(2*X, Y) ÷ min(2*X, Y). Below is the implementation : C++
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JavascriptTime Complexity: O(1) How do you make a even odd program in Python?num = int (input (“Enter any number to test whether it is odd or even: “) if (num % 2) == 0: print (“The number is even”) else: print (“The provided number is odd”) Output: Enter any number to test whether it is odd or even: 887 887 is odd. The program above only accepts integers as input.
How do you print even and odd list in Python?Python Program to Print Even and Odd Numbers in a List. num_list=[]. n=int(input("Enter the Starting of the range:")). k=int(input("Enter the Ending of the range:")). for i in range(n,k):. num_list. append(i). print("Original Number List:", num_list). even_list=[]. odd_list=[]. How do you program odd and even numbers?Program to Check Even or Odd
If the number is perfectly divisible by 2 , test expression number%2 == 0 evaluates to 1 (true). This means the number is even. However, if the test expression evaluates to 0 (false), the number is odd.
How do you print even and odd numbers in Python while loop?Python Code:
num = int(input("Enter a number: ")) mod = num % 2 if mod > 0: print("This is an odd number. ") else: print("This is an even number. ")
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