How to add a function to a class in python

Preface - a note on compatibility: other answers may only work in Python 2 - this answer should work perfectly well in Python 2 and 3. If writing Python 3 only, you might leave out explicitly inheriting from object, but otherwise the code should remain the same.

Adding a Method to an Existing Object Instance

I've read that it is possible to add a method to an existing object (e.g. not in the class definition) in Python.

I understand that it's not always a good decision to do so. But, how might one do this?

I don't recommend this. This is a bad idea. Don't do it.

Here's a couple of reasons:

  • You'll add a bound object to every instance you do this to. If you do this a lot, you'll probably waste a lot of memory. Bound methods are typically only created for the short duration of their call, and they then cease to exist when automatically garbage collected. If you do this manually, you'll have a name binding referencing the bound method - which will prevent its garbage collection on usage.
  • Object instances of a given type generally have its methods on all objects of that type. If you add methods elsewhere, some instances will have those methods and others will not. Programmers will not expect this, and you risk violating the rule of least surprise.
  • Since there are other really good reasons not to do this, you'll additionally give yourself a poor reputation if you do it.

Thus, I suggest that you not do this unless you have a really good reason. It is far better to define the correct method in the class definition or less preferably to monkey-patch the class directly, like this:

Foo.sample_method = sample_method

Since it's instructive, however, I'm going to show you some ways of doing this.

How it can be done

Here's some setup code. We need a class definition. It could be imported, but it really doesn't matter.

class Foo(object):
    '''An empty class to demonstrate adding a method to an instance'''

Create an instance:

foo = Foo()

Create a method to add to it:

def sample_method(self, bar, baz):
    print(bar + baz)

Method nought (0) - use the descriptor method, __get__

Dotted lookups on functions call the __get__ method of the function with the instance, binding the object to the method and thus creating a "bound method."

foo.sample_method = sample_method.__get__(foo)

and now:

>>> foo.sample_method(1,2)
3

Method one - types.MethodType

First, import types, from which we'll get the method constructor:

import types

Now we add the method to the instance. To do this, we require the MethodType constructor from the types module (which we imported above).

The argument signature for types.MethodType (in Python 3) is (function, instance):

foo.sample_method = types.MethodType(sample_method, foo)

and usage:

>>> foo.sample_method(1,2)
3

Parenthetically, in Python 2 the signature was (function, instance, class):

foo.sample_method = types.MethodType(sample_method, foo, Foo)

Method two: lexical binding

First, we create a wrapper function that binds the method to the instance:

def bind(instance, method):
    def binding_scope_fn(*args, **kwargs): 
        return method(instance, *args, **kwargs)
    return binding_scope_fn

usage:

>>> foo.sample_method = bind(foo, sample_method)    
>>> foo.sample_method(1,2)
3

Method three: functools.partial

A partial function applies the first argument(s) to a function (and optionally keyword arguments), and can later be called with the remaining arguments (and overriding keyword arguments). Thus:

>>> from functools import partial
>>> foo.sample_method = partial(sample_method, foo)
>>> foo.sample_method(1,2)
3    

This makes sense when you consider that bound methods are partial functions of the instance.

Unbound function as an object attribute - why this doesn't work:

If we try to add the sample_method in the same way as we might add it to the class, it is unbound from the instance, and doesn't take the implicit self as the first argument.

>>> foo.sample_method = sample_method
>>> foo.sample_method(1,2)
Traceback (most recent call last):
  File "", line 1, in 
TypeError: sample_method() takes exactly 3 arguments (2 given)

We can make the unbound function work by explicitly passing the instance (or anything, since this method doesn't actually use the self argument variable), but it would not be consistent with the expected signature of other instances (if we're monkey-patching this instance):

>>> foo.sample_method(foo, 1, 2)
3

Conclusion

You now know several ways you could do this, but in all seriousness - don't do this.

How do you add a function in Python?

How to Create User-Defined Functions in Python.
Use the def keyword to begin the function definition..
Name your function..
Supply one or more parameters. ... .
Enter lines of code that make your function do whatever it does. ... .
Use the return keyword at the end of the function to return the output..

How do you define a function in a class Python?

We must explicitly tell Python that it is a class method using the @classmethod decorator or classmethod() function. Class methods are defined inside a class, and it is pretty similar to defining a regular function. Like, inside an instance method, we use the self keyword to access or modify the instance variables.

What is __ add __ method in Python?

The __add__() method in Python specifies what happens when you call + on two objects. When you call obj1 + obj2, you are essentially calling obj1. __add__(obj2).

What is __ init __ function in classes?

The __init__ method is the Python equivalent of the C++ constructor in an object-oriented approach. The __init__ function is called every time an object is created from a class. The __init__ method lets the class initialize the object's attributes and serves no other purpose. It is only used within classes.