Input 5 output 12345 in python

I am new to python and I was practicing my coding skills with Hacker rank. I came across a question where I have to print numbers in a series one after another without adding any new line or white space in between them and most important is I cannot use the string method to get desired output.

For example if input is

3

then output should be

123

How can do it without string?

Please guide me...

Thanks in advance

asked Dec 10, 2016 at 16:12

1

You can use end keyword in print() method to avoid spaces:

num = int(input("Enter number: "))
for i in range(1, num+1):
    print(i, end='')

answered Dec 10, 2016 at 16:21

Yevhen KuzmovychYevhen Kuzmovych

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4

You may create a custom function using range() along with the usage of math.log10() as:

import math

def get_my_number(num):
    my_num = 0
    for i in range(1, num+1):
        digits = int(math.log10(i))+1  # count number of digits in number
        my_num = my_num * (10 ** digits) + i
    return my_num

Sample run:

>>> get_my_number(3)
123
>>> get_my_number(13)  # For number greater than 10
12345678910111213

This way you will get the actual value and you won't be just printing it on the console

answered Dec 10, 2016 at 16:17

Moinuddin QuadriMoinuddin Quadri

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2

for statement below takes elements starting from 1 to n.

• If you use "in range(n)" it would print the elements starting from 0 to n-1.
• If you use "in range(1,n)" it would print the elements starting from 1 to n-1.
• If you use "in range(1,n+1)" it would print the elements starting from 0 to n. And this is what you want.

printing without new line requires and addition in print command.

• end = "" would print 123 for example.

• end = " " with 1 space between would print 1 2 3 and so on.

  if __name__ == '__main__':
      n = int(input())
      for i in range(1,n+1):
          print (i, end = "")
  

answered Feb 15, 2021 at 11:09

n=int(input())

for i in range(n):    
    print(i+1, end="")

timgeb

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answered Dec 8, 2018 at 13:12

2

The following copy integer values to array ls before writing to a buffer pr and making a single write call (print):

n = int(input())
ls = []
pr = ("")
for i in range(1,n+1):
    ls.append(i)
for i in range(len(ls)):
    pr += "{}".format(ls[i])
print(pr)

answered Mar 11, 2021 at 18:12

2

If you want to print n natural number without using string then you can try this code:

n=int(input())
print(*range(1,n+1),sep="")

simple input: 5
output will be: 12345

Gino Mempin

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answered Dec 2, 2019 at 21:46

0

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