How do you repeat multiple times in python?

How do I make the code reapte such that users can guess the answer to the random number only three times, how do I make it stop at a point? Thanks. This is a random number guessing game, I'm a total beginner to python and can't find anything that helps me on the web (or it may be that I'm just dumb)

import random
print('what difficulty do you want? Type Easy or Hard accordingly')
difficulty = input('')

if difficulty == 'Hard':
    print('your going to have a tough time')
    hardrandomnum = random.randint(1,100)
    def main():
        print('try to guess the number')
        playerguess = float (input(""))
        if playerguess > hardrandomnum: 
            print ("guess a lower number")
        if playerguess < hardrandomnum:
            print("guess a higher number")
        if playerguess == hardrandomnum:
            print("correct") 
        

        restart = 4
        if restart >4:
            main()

        if restart == 4:
            exit()

main()

doctorlove

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asked Oct 12, 2021 at 12:54

2

Loops and breaks.

For example if you want to run the code three times wrap it in a for loop:

for i in range(3):
   [here goes your code]

or you could make a while loop and break:

while(True):
    [here goes your code]
    if condition is met:
        break

answered Oct 12, 2021 at 12:57

haxor789haxor789

5624 silver badges17 bronze badges

1

you could use a for loop:

for i in range(3):
    #your code 

the number in range() indicates how many times you visit the code inside there are also while loops but for your usecase a for loop should do the trick

answered Oct 12, 2021 at 13:00

R98R98

1091 silver badge9 bronze badges

1

Use a looping structure as below answer mentions.

Example with while loop

def repeat_user_input(num_tries=3):
    tries = 0
    result = []

    while tries < num_tries:
        tries += 1
        result.append(float(input()))

    return result


print(repeat_user_input())

Example with a list comprehension and range

def repeat_user_input(num_tries=3):
    return [float(input()) for _ in range(num_tries)]

answered Oct 12, 2021 at 13:04

rv.kvetchrv.kvetch

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I believe you are looking for something like the below?

import random
import sys
guess_counter = 0
random_number = 0
easy_hard = input('Chose your difficulty lever by typing "easy" or "hard" ')
if easy_hard.lower() == 'easy':
    print('Your in luck! You are about to have fun')
    random_number = random.randint(1,10)
elif easy_hard.lower() == 'hard':
    print('Woow this game is not going to be easy')
    random_number = random.randint(1,100)
else:
    print('You need to type either easy or hard and nothing else')
    sys.exit()
while guess_counter < 4:
    user_number = int(input('Guess: ')) 
    if user_number < random_number:
        print('Try higher number')
        guess_counter += 1
    elif user_number > random_number:
        print('Trye lower number')
        guess_counter += 1
    else:
        print('Congrats! You Won')
        break
else:
    print('Ooops! Looks like you luck run out.')

answered Oct 12, 2021 at 13:27

pyzerpyzer

1227 bronze badges

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