Pass filename as argument python

I have the following code in .py file:

import re

regex = re.compile(
    r"""ULLAT:\ (?P-?[\d.]+).*?
    ULLON:\ (?P-?[\d.]+).*?
    LRLAT:\ (?P-?[\d.]+)""", re.DOTALL|re.VERBOSE)

I have the data in .txt file as a sequence:

QUADNAME: rockport_colony_SD
RESOLUTION: 10 ULLAT: 43.625 ULLON:
-97.87527466 LRLAT: 43.5 LRLON: -97.75027466 HDATUM: 27 ZMIN: 361.58401489 ZMAX: 413.38400269 ZMEAN: 396.1293335 ZSIGMA: 12.36359215 PMETHOD: 5 QUADDATE: 20001001

How can I use the Python -file to process the .txt -file?

I guess that we need a parameter in the .py file, so that we can use a syntax like in terminal:

$ py-file file-to-be-processed

This question was raised by the post here.

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To use it, you just pass a path or filename into a new Path() object using forward slashes and it handles the rest: Notice two things here: You should use forward slashes with pathlib functions. The Path() object will convert forward slashes into the correct kind of slash for the current operating system.

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