Pass filename as argument python
I have the following code in .py file: Show
I have the data in .txt file as a sequence:
How can I use the Python -file to process the .txt -file? I guess that we need a parameter in the .py file, so that we can use a syntax like in terminal:
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How do you pass a file path as a command line argument in Python?To use it, you just pass a path or filename into a new Path() object using forward slashes and it handles the rest: Notice two things here: You should use forward slashes with pathlib functions. The Path() object will convert forward slashes into the correct kind of slash for the current operating system.
How do you input a filename in Python?inputFileName = input("Enter name of input file: ") inputFile = open(inputFileName, "r") print("Opening file", inputFileName, " for reading.") 1. Open the file and associate the file with a file variable (file is “locked” for writing).
How read a file from command line in Python?To read a text file in Python, you follow these steps: First, open a text file for reading by using the open() function. Second, read text from the text file using the file read() , readline() , or readlines() method of the file object.
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1) open() function.. |