Print odd numbers using while loop in python
View Discussion Show Improve Article Save Article View Discussion Improve Article Save Article Given a list of numbers, write a Python program to print all odd numbers in given list. Example: Input: list1 = [2, 7, 5, 64, 14] Output: [7, 5] Input: list2 = [12, 14, 95, 3, 73] Output: [95, 3, 73]
Python3
21 45 93
Python3
21 45 93
Python3
21 45 93
Python3
Odd numbers in the list: [21, 45, 93, 11] Method: Using passPython3
Method: Using recursionPython3
Output odd numbers in the list: 21 45 93 11 Method: Using enumerate functionPython3
Auxiliary Space: O(1) How do you print a odd number in a while loop in Python?Using for loop : Iterate each element in the list using for loop and check if num % 2 != 0. If the condition satisfies, then only print the number.
How do you print odd numbers in a loop?Logic to print odd numbers from 1 to n without if statement. Input upper limit to print odd number from user. Store it in some variable say N .. Run a loop from 1 to N , increment it by 2 for each iteration. The loop structure should look like for(i=1; i<=N; i+=2) .. Inside the loop body print the value of i .. How do you find the odd number in a while loop?Using while loop by checking the condition number<=n (value of number is less than or equal to n) - this will execute the loop until the value of number is less than or equal to n. Then, within the loop, we are checking the condition to check whether number is ODD or not, the condition is (number%2 !=
How do you write odd numbers in Python?num = int (input (“Enter any number to test whether it is odd or even: “) if (num % 2) == 0: print (“The number is even”) else: print (“The provided number is odd”) Output: Enter any number to test whether it is odd or even: 887 887 is odd.
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